Submission #31757

#TimeUsernameProblemLanguageResultExecution timeMemory
31757aomeK blocks (IZhO14_blocks)C++14
100 / 100
373 ms4172 KiB
#include <bits/stdc++.h> #define fi first #define se second using namespace std; typedef pair<int, int> ii; typedef pair<int, ii> p; const int N = 100005; const int INF = 1e9; int n, k, f[2][N], a[N]; int main() { // freopen("in.txt", "r", stdin); // freopen("out.txt", "w", stdout); ios::sync_with_stdio(false); cin >> n >> k; for (int i = 1; i <= n; ++i) cin >> a[i]; for (int i = 1; i <= n; ++i) f[0][i] = INF; for (int i = 1; i <= k; ++i) { bool t = i & 1; stack<p> st[2]; f[t][0] = INF; for (int j = 1; j <= n; ++j) { int pos = j; int val = f[t ^ 1][j - 1]; while (st[0].size() && a[st[0].top().fi] <= a[j]) { pos = st[0].top().se.fi; val = min(val, st[0].top().se.se); st[0].pop(); } st[0].push(p(j, ii(pos, val))); while (st[1].size() && st[1].top().se.fi >= pos) st[1].pop(); if (!(st[1].size() && st[1].top().se.se <= val + a[j])) { st[1].push(p(j, ii(pos, val + a[j]))); } f[t][j] = st[1].top().se.se; //cout << pos << ' ' << val << ' ' << f[t][j] << ' ' << j << '\n'; } } cout << f[k & 1][n]; }
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