| # | Time | Username | Problem | Language | Result | Execution time | Memory | 
|---|---|---|---|---|---|---|---|
| 314077 | phathnv | Mobitel (COCI19_mobitel) | C++11 | 3520 ms | 5636 KiB | 
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#define mp make_pair
#define X first
#define Y second
#define taskname "MOBITEL"
using namespace std;
typedef long long ll;
typedef pair <int, int> ii;
const int R = 301;
const int sqrtN = 1001;
const int MOD = 1e9 + 7;
int r, c, n, a[R][R];
int s, dp[2][R][2][sqrtN];
void readInput(){
    scanf("%d %d %d", &r, &c, &n);
    for(int i = 1; i <= r; i++)
        for(int j = 1; j <= c; j++)
            scanf("%d", &a[i][j]);
}
void add(int &x, const int &y){
    x += y;
    x -= (x >= MOD) * MOD;
}
void nextState(int &k, int &p, int factor){
    if (k == 1){
        p = (p + factor - 1) / factor;
    } else {
        ll tmp = (ll) p * factor;
        if (tmp >= s){
            k = 1;
            p = (n + tmp - 1) / tmp;
        } else {
            p = tmp;
        }
    }
}
void solve(){
    s = ceil(sqrt(n));
    dp[0][1][0][1] = 1;
    for(int i = 0; i < r; i++){
        int id = i & 1;
        for(int j = 1; j <= c; j++)
            for(int k = 0; k < 2; k++)
                for(int p = 0; p <= s; p++)
                    dp[id ^ 1][j][k][p] = 0;
        for(int j = 1; j <= c; j++)
            for(int k = 0; k < 2; k++)
                for(int p = 0; p <= s; p++){
                    if (!dp[id][j][k][p])
                        continue;
                    int nxtK = k;
                    int nxtP = p;
                    nextState(nxtK, nxtP, a[i + 1][j]);
                    add(dp[id ^ 1][j][nxtK][nxtP], dp[id][j][k][p]);
                }
        for(int j = 1; j < c; j++)
            for(int k = 0; k < 2; k++)
                for(int p = 0; p <= s; p++){
                    if (!dp[id ^ 1][j][k][p])
                        continue;
                    int nxtK = k;
                    int nxtP = p;
                    nextState(nxtK, nxtP, a[i + 1][j + 1]);
                    add(dp[id ^ 1][j + 1][nxtK][nxtP], dp[id ^ 1][j][k][p]);
                }
    }
    printf("%d", dp[r & 1][c][1][1]);
}
int main(){
    if (fopen(taskname".inp", "r")){
        freopen(taskname".inp", "r", stdin);
        freopen(taskname".out", "w", stdout);
    }
    readInput();
    solve();
    return 0;
}
Compilation message (stderr)
| # | Verdict | Execution time | Memory | Grader output | 
|---|---|---|---|---|
| Fetching results... | ||||
