Submission #311142

#	Time	Username	Problem	Language	Result	Execution time	Memory
311142		shivensinha4	Cake (CEOI14_cake)	C++17	0 / 100	78 ms	16548 KiB

cake

#include <bits/stdc++.h> 
using namespace std; 
#define for_(i, s, e) for (int i = s; i < (int) e; i++)
#define for__(i, s, e) for (ll i = s; i < e; i++)
typedef long long ll;
typedef vector<int> vi;
typedef pair<int, int> ii;
#define endl '\n'

class SegmentTree {
	private:
		vi tree, raw; int n;
		
		int merge(int a, int b) {
			return max(a, b);
		}
		
		void buildTree(int l, int r, int p) {
			if (l == r) {
				tree[p] = raw[l];
				return;
			}
			
			int mid = (l + r) / 2;
			int c1 = 2*p+1, c2 = 2*p+2;
			buildTree(l, mid, c1); buildTree(mid+1, r, c2);
			tree[p] = merge(tree[c1], tree[c2]);
		}
		
		void update(int i, int val, int l, int r, int p) {
			if (l > i or r < i) return;
			if (l == r) {
				tree[p] = val;
				return;
			}
			
			int mid = (l + r) / 2;
			int c1 = 2*p+1, c2 = 2*p+2;
			update(i, val, l, mid, c1); update(i, val, mid+1, r, c2);
			tree[p] = merge(tree[c1], tree[c2]);
		}
		
		int mx(int i, int j, int l, int r, int p) {
			if (l > j or r < i) return 0;
			if (l >= i and r <= j) return tree[p];
			
			int mid = (l + r) / 2;
			int c1 = 2*p+1, c2 = 2*p+2;
			return merge(mx(i, j, l, mid, c1), mx(i, j, mid+1, r, c2));
		}
	
	public: 
		SegmentTree(vi input) {
			raw = input;
			n = raw.size();
			tree.resize(4*n);
			buildTree(0, n-1, 0);
		}
		
		int mx(int i, int j) {
			return mx(i, j, 0, n-1, 0);
		}
		
		void update(int i, int val) {
			update(i, val, 0, n-1, 0);
		}
};

const int MXV = 750000;
int pos[MXV+2];

int main() {
	#ifdef shiven
	freopen("test.in", "r", stdin);
	#endif
	
	ios_base::sync_with_stdio(false);
	cin.tie(0);
	
	int n, a, q; cin >> n >> a;
	a -= 1;
	vi nums(n);
	for_(i, 0, n) {
		cin >> nums[i];
		pos[nums[i]] = i;
	}
	SegmentTree tree(nums);
	vi mod = nums;
	sort(mod.begin(), mod.end(), greater<int>());
	set<ii, greater<ii>> s;
	for_(i, 0, min(10, n)) s.insert({mod[i], i});
	
	cin >> q;
	while (q--) {
		char c; cin >> c;
		if (c == 'F') {
			int k; cin >> k;
			k -= 1;
			
			if (k == a) {
				cout << 0 << endl;
				continue;
			}
			int bef = abs(k-a), lo, hi, ans, largest = tree.mx(min(a, k), max(a, k));
			if (k < a) {
				lo = a+1, hi = ans = n;
				while (lo < hi) {
					int mid = (lo+hi)/2;
					if (tree.mx(a+1, mid) >= largest) {
						ans = hi = mid;
					} else {
						lo = mid+1;
					}
				}
			} else {
				lo = 0, hi = a, ans = -1;
				while (lo < hi) {
					int mid = (lo+hi)/2;
					if (tree.mx(mid, a-1) >= largest) {
						ans = mid;
						lo = mid+1;
					} else {
						hi = mid;
					}
				}
			}
			
			cout << bef+abs(ans-a)-1 << endl;
		} else {
			assert(false);
			//cout << "current set of elements is: ";
			//for (auto i: s) cout << i.first << " ";
			//cout << endl;
			int x, y; cin >> x >> y;
			set<ii, greater<ii>> ss;
			x -= 1; y -= 1;
			int pt = 0, nv = -1;
			for (auto i: s) {
				if (ss.size()+1 == s.size()) break;
				else if (pt >= y) {
					if (i.second != x) {
						if (nv == -1) nv = i.first+1;
						ss.insert(i);
					}
				}
				else {
					tree.update(i.second, i.first+1);
					nums[i.second] += 1;
					ss.insert({i.first+1, i.second});	
					nv = i.first;
				}
				pt++;
			}
			
			//cout << "get new value " << nv << endl;
			tree.update(x, nv);
			ss.insert({nv, x});
			nums[x] = nv;
			swap(s, ss);
			//cout << "new set of elements is: ";
			//for (auto i: s) cout << i.first << " ";
			//cout << endl;
		}
	}

	return 0;
}

• Subtask 1: 0 / 15
• Subtask 2: 0 / 15
• Subtask 3: 0 / 20
• Subtask 4: 0 / 50