Submission #310907

#TimeUsernameProblemLanguageResultExecution timeMemory
310907HynDufPotemkin cycle (CEOI15_indcyc)C++11
100 / 100
345 ms90232 KiB
#include <bits/stdc++.h> #define task "I" #define all(v) (v).begin(), (v).end() #define rep(i, l, r) for (int i = (l); i <= (r); ++i) #define Rep(i, r, l) for (int i = (r); i >= (l); --i) #define DB(X) { cerr << #X << " = " << (X) << '\n'; } #define DB1(A, _) { cerr << #A << "[" << _ << "] = " << (A[_]) << '\n'; } #define DB2(A, _, __) { cerr << #A << "[" << _ << "][" << __ << "] = " << (A[_][__]) << '\n'; } #define DB3(A, _, __, ___) { cerr << #A << "[" << _ << "][" << __ << "][" << ___ << "] = " << (A[_][__][___]) << '\n'; } #define PR(A, l, r) { cerr << '\n'; rep(_, l, r) DB1(A, _); cerr << '\n';} #define SZ(x) ((int)(x).size()) #define pb push_back #define eb emplace_back #define pf push_front #define F first #define S second #define by(x) [](const auto& a, const auto& b) { return a.x < b.x; } // sort(arr, arr + N, by(a)); #define next ___next #define prev ___prev #define y1 ___y1 #define left ___left #define right ___right #define y0 ___y0 #define div ___div #define j0 ___j0 #define jn ___jn using ll = long long; using ld = long double; using ull = unsigned long long; using namespace std; typedef pair<int, int> ii; typedef pair<ii, int> iii; typedef vector<int> vi; typedef vector<ii> vii; typedef vector<ll> vl; const int N = 1001, NN = 1e5 + 1; int n, m, par[NN << 1]; bool d[N][N], in[NN << 1]; vi g[N], gr[NN << 1]; ii edge[NN]; vi res; void dfs(int u, int p) { in[u] = 1; par[u] = p; for (int v : gr[u]) { if (par[v] == -1) dfs(v, u); else if (in[v] && res.empty()) { while (u != v) { res.eb(edge[u >> 1].F); res.eb(edge[u >> 1].S); u = par[u]; } res.eb(edge[v >> 1].F); res.eb(edge[v >> 1].S); return; } } in[u] = 0; } void fix() { for (int i = 2; i < SZ(res); i += 2) if (res[i] != res[i - 1]) swap(res[i], res[i + 1]); } int main() { #ifdef HynDuf freopen(task".in", "r", stdin); //freopen(task".out", "w", stdout); #else ios_base::sync_with_stdio(false); cin.tie(nullptr); #endif cin >> n >> m; rep(i, 0, m - 1) { int u, v; cin >> u >> v; g[u].eb(i); g[v].eb(i); d[u][v] = d[v][u] = 1; edge[i] = {u, v}; } rep(i, 0, m - 1) { int u = edge[i].F, v = edge[i].S; for (int j : g[v]) if (j != i) { int id = (edge[j].F == v) ? (j << 1) : ((j << 1) | 1), w = (edge[j].F == v) ? edge[j].S : edge[j].F; if (d[u][w]) continue; gr[i << 1].eb(id); } for (int j : g[u]) if (j != i) { int id = (edge[j].F == u) ? (j << 1) : ((j << 1) | 1), w = (edge[j].F == u) ? edge[j].S : edge[j].F; if (d[v][w]) continue; gr[(i << 1) | 1].eb(id); } } fill(par, par + 2 * m, -1); rep(i, 0, 2 * m - 1) if (par[i] == -1 && res.empty()) dfs(i, i); if (res.empty()) { cout << "no"; return 0; } fix(); if (res[1] != res[2]) { swap(res[0], res[1]); fix(); } for (int i = 0; i < SZ(res); i += 2) cout << res[i] << ' '; return 0; }
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