# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
310446 | Marlov | Automobil (COCI17_automobil) | C++14 | 546 ms | 16124 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
/*
Code by @marlov
*/
#include <iostream>
#include <fstream>
#include <string>
#include <sstream>
#include <vector>
#include <string>
#include <cmath>
#include <algorithm>
#include <iomanip>
#include <utility>
#include <set>
#include <unordered_set>
#include <map>
#include <unordered_map>
#include <stack>
#include <queue>
#include <iterator>
using namespace std;
typedef long long ll;
typedef pair<long long,long long> pi;
#define maxV 1000002
#define MOD 1000000007
//const long long MOD=1000000007;
long long N,M,K;
long long sum=0;
unordered_set<long long> cols;
unordered_set<long long> rows;
long long cm[maxV];
long long rm[maxV];
long long power(long long base,long long exp){
if(exp==1) return base;
long long save=power(base,exp/2);
save*=save;
save%=MOD;
if(exp%2==1) save*=base;
return save%MOD;
}
long long add(long long a,long long b){
a+=b;
while(a<0) a+=MOD;
return a%MOD;
}
long long sub(long long a,long long b){
a-=b;
while(a<0) a+=MOD;
return a%MOD;
}
long long mult(long long a,long long b){
a*=b;
return a%MOD;
}
long long qsum(long long T,long long s,long long e){
T%=MOD;
s%=MOD;
e%=MOD;
if(T%2==0) return mult(T*power(2,MOD-2),add(s,e));
else return mult(T,add(s,e)*power(2,MOD-2));
}
int main() {
ios_base::sync_with_stdio(0); cin.tie(0);
cin>>N>>M>>K;
fill(cm,cm+maxV,1);
fill(rm,rm+maxV,1);
char c;
long long x,m;
for(long long i=0;i<K;i++){
cin>>c>>x>>m;
x--;
if(c=='R'){
rows.insert(x);
rm[x]=mult(rm[x],m);
}else if(c=='S'){
cols.insert(x);
cm[x]=mult(cm[x],m);
}
}
for(long long i=0;i<N;i++){
sum=add( sum , mult(rm[i],(qsum(M,mult(i,M)+1,mult(i,M)+M))) );
}
for(long long i=0;i<M;i++){
sum=add(sum, mult(sub(cm[i],1),(qsum(N,i+1,mult(N-1,M)+i+1))) );
}
for(long long i:cols){
for(long long j:rows){
long long cv=add(mult(M,j),i+1);
sum=sub(sum,mult(add(sub(cm[i],1),rm[j]),cv) );
sum=add(sum, mult( mult(cm[i],rm[j]), cv) );
}
}
cout<<sum<<'\n';
return 0;
}
/* stuff you should look for
* long long overflow, array bounds
* special cases (n=1,n=0?)
* do smth instead of nothing and stay organized
*/
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