Submission #307601

#	Time	Username	Problem	Language	Result	Execution time	Memory
307601		MarcoMeijer	Potatoes and fertilizers (LMIO19_bulves)	C++14	54 / 100	232 ms	262148 KiB

bulves

#include <bits/stdc++.h>
using namespace std;
 
// macros
typedef long long ll;
typedef long double ld;
typedef pair<int, int> ii;
typedef pair<ll, ll> lll;
typedef tuple<int, int, int> iii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef vector<iii> viii;
typedef vector<ll> vll;
typedef vector<lll> vlll;
#define REP(a,b,c) for(int a=int(b); a<int(c); a++)
#define RE(a,c) REP(a,0,c)
#define RE1(a,c) REP(a,1,c+1)
#define REI(a,b,c) REP(a,b,c+1)
#define REV(a,b,c) for(int a=int(c-1); a>=int(b); a--)
#define FOR(a,b) for(auto& a : b)
#define all(a) a.begin(), a.end()
#define INF 1e18
#define EPS 1e-9
#define pb push_back
#define popb pop_back
#define fi first
#define se second
#define sz size()
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
 
// input
template<class T> void IN(T& x) {cin >> x;}
template<class H, class... T> void IN(H& h, T&... t) {IN(h); IN(t...); }
 
// output
template<class T1, class T2> void OUT(const pair<T1,T2>& x);
template<class T> void OUT(const vector<T>& x);
template<class T> void OUT(const T& x) {cout << x;}
template<class H, class... T> void OUT(const H& h, const T&... t) {OUT(h); OUT(t...); }
template<class T1, class T2> void OUT(const pair<T1,T2>& x) {OUT(x.fi,' ',x.se);}
template<class T> void OUT(const vector<T>& x) {RE(i,x.size()) OUT(i==0?"":" ",x[i]);}
template<class... T> void OUTL(const T&... t) {OUT(t..., "\n"); }
template<class H> void OUTLS(const H& h) {OUTL(h); }
template<class H, class... T> void OUTLS(const H& h, const T&... t) {OUT(h,' '); OUTLS(t...); }
 
//===================//
//  Added libraries  //
//===================//
 
//===================//
//end added libraries//
//===================//
 
void program();
int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
    program();
}
 
 
//===================//
//   begin program   //
//===================//
 
const int MX = 5e5+2;

ll n;
ll a[MX], b[MX], dif[MX], d[MX];
vll prevDP, curDP;

void program() {
    IN(n);
    RE(i,n) IN(a[i],b[i]);
    RE(i,n) dif[i] = a[i]-b[i];

    d[0]=0;
    RE(i,n) d[i+1] = d[i] + dif[i];
    curDP.assign(d[n]+1, 0);
    RE(i,n) {
        prevDP = curDP;
        curDP.assign(d[n]+1,INF);
        RE(j,d[n]+1) {
            if(j) curDP[j] = min(curDP[j], curDP[j-1]);
            curDP[j] = min(curDP[j], abs(d[i]-(ll)j) + (i ? prevDP[j] : 0ll));
        }
    }
    OUTL(curDP[d[n]]);
}

• Subtask 1: 24 / 24
• Subtask 2: 10 / 10
• Subtask 3: 20 / 20
• Subtask 4: 0 / 10
• Subtask 5: 0 / 36