Submission #307548

#TimeUsernameProblemLanguageResultExecution timeMemory
307548HynDufCeste (COCI17_ceste)C++11
160 / 160
510 ms12908 KiB
#include <bits/stdc++.h> #define task "C" #define all(v) (v).begin(), (v).end() #define rep(i, l, r) for (int i = (l); i <= (r); ++i) #define Rep(i, r, l) for (int i = (r); i >= (l); --i) #define DB(X) { cerr << #X << " = " << (X) << '\n'; } #define DB1(A, _) { cerr << #A << "[" << _ << "] = " << (A[_]) << '\n'; } #define DB2(A, _, __) { cerr << #A << "[" << _ << "][" << __ << "] = " << (A[_][__]) << '\n'; } #define DB3(A, _, __, ___) { cerr << #A << "[" << _ << "][" << __ << "][" << ___ << "] = " << (A[_][__][___]) << '\n'; } #define PR(A, l, r) { cerr << '\n'; rep(_, l, r) DB1(A, _); cerr << '\n';} #define SZ(x) ((int)(x).size()) #define pb push_back #define eb emplace_back #define pf push_front #define F first #define S second #define by(x) [](const auto& a, const auto& b) { return a.x < b.x; } // sort(arr, arr + N, by(a)); #define next ___next #define prev ___prev #define y1 ___y1 #define left ___left #define right ___right #define y0 ___y0 #define div ___div #define j0 ___j0 #define jn ___jn using ll = long long; using ld = long double; using ull = unsigned long long; using namespace std; typedef pair<int, int> ii; typedef pair<int, ii> iii; typedef vector<int> vi; typedef vector<ii> vii; typedef vector<iii> viii; typedef vector<ll> vl; const int N = 2002; int n, m, mnCost[N]; ll ans[N]; viii g[N]; int main() { #ifdef HynDuf freopen(task".in", "r", stdin); //freopen(task".out", "w", stdout); #else ios_base::sync_with_stdio(false); cin.tie(nullptr); #endif cin >> n >> m; rep(i, 1, m) { int u, v, t, c; cin >> u >> v >> t >> c; g[u].pb({v, {t, c}}); g[v].pb({u, {t, c}}); } fill(ans, ans + 1 + n, 1e18); fill(mnCost, mnCost + 1 + n, 1e9); priority_queue<iii, viii, greater<iii> > pq; pq.push({0, {0, 1}}); ans[1] = 0; while (!pq.empty()) { int u = pq.top().S.S, t = pq.top().F, c = pq.top().S.F; pq.pop(); if (c >= mnCost[u]) continue; mnCost[u] = c; ans[u] = min(ans[u], t * 1LL * c); for (iii E : g[u]) { pq.push({t + E.S.F, {c + E.S.S, E.F}}); } } rep(i, 2, n) cout << (ans[i] == 1e18 ? -1 : ans[i]) << '\n'; return 0; }
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