Submission #307414

#TimeUsernameProblemLanguageResultExecution timeMemory
307414syyConnecting Supertrees (IOI20_supertrees)C++17
21 / 100
271 ms26232 KiB
#include "supertrees.h" #include <bits/stdc++.h> using namespace std; typedef long long ll; typedef long double ld; #define FOR(i, a, b) for(int i = (int)a; i <= (int)b; i++) #define DEC(i, a, b) for(int i = (int)a; i >= (int)b; i--) typedef pair<int, int> pi; typedef pair<pi, int> pii; typedef pair<pi, pi> pipi; #define f first #define s second typedef vector<int> vi; typedef vector<pi> vpi; typedef vector<pii> vpii; #define pb push_back #define pf push_front #define all(v) v.begin(), v.end() #define disc(v) sort(all(v)); v.resize(unique(all(v)) - v.begin()); #define INF (int) 1e9 + 100 #define LLINF (ll) 1e18 #define fastio ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0) #define sandybridge __attribute__((optimize("Ofast"), target("arch=sandybridge"))) mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); //can be used by calling rng() or shuffle(A, A+n, rng) inline ll rand(ll x, ll y) { ++y; return (rng() % (y-x)) + x; } //inclusivesss int n, p[1005]; vi comp[1005]; bool vis[1005], isline[1005]; int fs(int x) { if (p[x] == x) return x; return p[x] = fs(p[x]); } int construct(vector<vector<int>> v) { n = v.size(); vector<vi> ans = vector<vi>(n, vi(n, 0)); vector<vi> check = vector<vi>(n, vi(n, 0)); FOR(i, 0, n-1) p[i] = i; FOR(i, 0, n-1) FOR(j, 0, n-1) if (v[i][j]) p[fs(i)] = fs(j); FOR(i, 0, n-1) comp[fs(i)].pb(i); FOR(it, 0, n-1) { vi line, cyc; for (auto i:comp[it]) { bool ok = 0; for (auto j:comp[it]) if (i != j and v[i][j] == 1) ok = 1; (ok ? line : cyc).pb(i); if (ok) isline[i] = 1; } for (auto i:line) { if (vis[i]) continue; vis[i] = 1; cyc.pb(i); int pre = i; FOR(j, 0, n-1) if (i != j and v[i][j] == 1 and isline[j]) { ans[pre][j] = ans[j][pre] = 1; pre = j; vis[j] = 1; } } FOR(i, 1, cyc.size()-1) ans[cyc[i-1]][cyc[i]] = ans[cyc[i]][cyc[i-1]] = 1; if (cyc.size() > 1) ans[cyc[0]][cyc.back()] = ans[cyc.back()][cyc[0]] = 1; for (auto i:comp[it]) for (auto j:comp[it]) { if (!isline[i] or !isline[j]) check[i][j] = 2; else check[i][j] = 1; if (i == j) check[i][j] = 1; } } if (check != v) return 0; build(ans); return 1; }
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