Submission #307233

#	Time	Username	Problem	Language	Result	Execution time	Memory
307233		VEGAnn	Comparing Plants (IOI20_plants)	C++14	0 / 100	4064 ms	384 KiB

plants

#include "plants.h"
#include <bits/stdc++.h>
#define PB push_back
#define sz(x) ((int)x.size())
using namespace std;
const int N = 5010;
const int oo = 2e9;
queue<int> q;
vector<int> vc;
int per[N], mrk[N], tt = 0;
bool sml[N][N], g[N][N];

void init(int k, vector<int> r) {
    int n = sz(r);

    for (int it = n - 1; it >= 0; it--){
        vc.clear();

        for (int i = 0; i < n; i++)
            if (r[i] == 0)
                vc.PB(i);

        if (sz(vc) == 0){
            while (1) {}
        }

        int cand = -1, mx = -1;

        for (int it = 0; it < sz(vc); it++){
            int cur = vc[it];
            int pre = vc[(it + sz(vc) - 1) % sz(vc)];

            if (pre < cur){
                if (cur - pre > mx){
                    mx = cur - pre;
                    cand = cur;
                    break;
                }
            } else {
                if (cur - pre + n > mx){
                    mx = cur - pre + n;
                    cand = cur;
                    break;
                }
            }
        }

        per[cand] = it;
        r[cand] = oo;

        for (int i = 1, loc = cand; i < k; i++){
            loc = (loc + n - 1) % n;

            r[loc]--;

            if (r[loc] < oo / 2)
                g[cand][loc] = 1;
        }

        for (int i = 1, loc = cand; i < k; i++){
            loc = (loc + 1) % n;

            if (r[loc] < oo / 2)
                g[cand][loc] = 1;
        }
    }

    for (int i = 0; i < n; i++){
        tt++;

        q.push(i);
        mrk[i] = tt;

        while (sz(q)){
            int v = q.front(); q.pop();

            sml[i][v] = 1;

            for (int u = 0; u < n; u++)
                if (g[v][u] && mrk[u] < tt){
                    mrk[u] = tt;
                    q.push(u);
                }
        }
    }

    return;
}

int compare_plants(int x, int y) {
    if (sml[x][y]) return 1;
    if (sml[y][x]) return -1;
    return 0;
}

• Subtask 1: 0 / 5
• Subtask 2: 0 / 14
• Subtask 3: 0 / 13
• Subtask 4: 0 / 17
• Subtask 5: 0 / 11
• Subtask 6: 0 / 15
• Subtask 7: 0 / 25