Submission #306157

#	Time	Username	Problem	Language	Result	Execution time	Memory
306157		richyrich	Arranging Shoes (IOI19_shoes)	C++17	10 / 100	1088 ms	23932 KiB

shoes

//#include "shoes.h"
#include<bits/stdc++.h>
using namespace std;
using ll = long long;
set<pair<ll, ll>> left_shoes;
ll n, now,idx, ans;
map<ll, set<ll>>i_r_shoes; 
queue<pair<ll, ll>> q;
void shift() {
    for(auto c : left_shoes) {
            ll IDX = c.first;
            if(now <= IDX && IDX <= idx) {
                ans++;
                q.push({IDX, c.second});
            }
        }
        while(!q.empty()) {
            ll a = q.front().first , b = q.front().second;
            left_shoes.erase({a, b});
            left_shoes.insert({a + 1, b});
            q.pop();
        }
        for(auto &c : i_r_shoes) {
            queue<ll> q_p;
            for(ll d : c.second) { 
                if(now <= d && d <= idx) q_p.push(d), ans++;
            }
            while(!q_p.empty()) {
                ll a = q_p.front();
                //if(c.second.find(a) != c.second.end()) prllf("YES\n");
                c.second.erase(a);
                c.second.insert(a+1);
                //prllf("now %d %d\n", c.first, a+1);
                q_p.pop();
            }
        }
}
long long count_swaps(std::vector<int> s) {
    n = s.size();
    for(ll i = 0; i < n; i++) {
        if(s[i] < 0) left_shoes.insert({i, s[i]});
        else i_r_shoes[s[i]].insert(i);
    }
    while(!left_shoes.empty()) {
        idx = (*left_shoes.begin()).first;
        ll type = (*left_shoes.begin()).second;
        left_shoes.erase({idx, type});
        shift();
        now++;

        /*prllf("here --> %d  %d \n", type, idx);
        for(auto c : left_shoes) {
            prllf("%d %d\n", c.second, c.first);
        }
        for(auto c : i_r_shoes) {
            for(auto d : c.second)prllf("%d %d\n", c.first, d);
        }
*/

        idx = *i_r_shoes[-type].begin();
        i_r_shoes[-type].erase(idx);
        shift();
        now++;/*
        prllf("%d\n", ans);
        for(auto c : left_shoes) {
            prllf("%d %d\n", c.second, c.first);
        }
        for(auto c : i_r_shoes) {
            for(auto d : c.second)prllf("%d %d\n", c.first, d);
        }*/
    }
    return ans;
}

• Subtask 1: 10 / 10
• Subtask 2: 0 / 20
• Subtask 3: 0 / 20
• Subtask 4: 0 / 15
• Subtask 5: 0 / 20
• Subtask 6: 0 / 15