Submission #305841

#	Time	Username	Problem	Language	Result	Execution time	Memory
305841		HynDuf	Brunhilda’s Birthday (BOI13_brunhilda)	C++11	0 / 100	1105 ms	79960 KiB

brunhilda

#include <bits/stdc++.h>

#define task "B"
#define all(v) (v).begin(), (v).end()
#define rep(i, l, r) for (int i = (l); i <= (r); ++i)
#define Rep(i, r, l) for (int i = (r); i >= (l); --i)
#define DB(X) { cerr << #X << " = " << (X) << '\n'; }
#define DB1(A, _) { cerr << #A << "[" << _ << "] = " << (A[_]) << '\n'; }
#define DB2(A, _, __) { cerr << #A << "[" << _ << "][" << __ << "] = " << (A[_][__]) << '\n'; }
#define DB3(A, _, __, ___) { cerr << #A << "[" << _ << "][" << __ << "][" << ___ << "] = " << (A[_][__][___]) << '\n'; }
#define PR(A, l, r) { cerr << '\n'; rep(_, l, r) DB1(A, _); cerr << '\n';}
#define SZ(x) ((int)(x).size())
#define pb push_back
#define eb emplace_back
#define pf push_front
#define F first
#define S second
#define by(x) [](const auto& a, const auto& b) { return a.x < b.x; } // sort(arr, arr + N, by(a));
#define next ___next
#define prev ___prev
#define y1 ___y1
#define left ___left
#define right ___right
#define y0 ___y0
#define div ___div
#define j0 ___j0
#define jn ___jn

using ll = long long;
using ld = long double;
using ull = unsigned long long;
using namespace std;
typedef pair<int, int> ii;
typedef pair<ii, int> iii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef vector<ll> vl;
const int N = 1e5 + 2, NN = 2e7 - 1;
int n, q, dp[NN + 2];
int main()
{
#ifdef HynDuf
    freopen(task".in", "r", stdin);
    //freopen(task".out", "w", stdout);
#else
    ios_base::sync_with_stdio(false); cin.tie(nullptr);
#endif
    cin >> n >> q;
    ll lcm = 1;
    rep(i, 1, n)
    {
        int p;
        cin >> p;
        for (int j = p - 1; j <= NN; j++) dp[j] = p - 1;
        lcm = min(N * 100LL, lcm * p);
    }
    Rep(i, NN - 1, 1) dp[i] = max(dp[i], dp[i + 1] - 1);
    rep(i, 1, NN) dp[i] = dp[i - dp[i]] + 1;
    while (q--)
    {
        int x;
        cin >> x;
        if (x >= lcm) cout << "oo\n";
        else cout << dp[x] << '\n';
    }
    return 0;
}

• Subtask 1: 0 / 20
• Subtask 2: 0 / 20
• Subtask 3: 0 / 60