This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#define pb push_back
#define eb emplace_back
#define sz(V) ((int)(V).size())
#define allv(V) ((V).begin()),((V).end())
#define befv(V) ((V)[(sz(V)-2)])
#define sorv(V) sort(allv(V))
#define revv(V) reverse(allv(V))
#define univ(V) (V).erase(unique(allv(V)),(V).end())
#define clv(V) (V).clear()
#define upmin(a,b) (a)=min((a),(b))
#define upmax(a,b) (a)=max((a),(b))
#define INF (0x3f3f3f3f)
#define INFLL (0x3f3f3f3f3f3f3f3fll)
using namespace std;
typedef long long ll;
void fg(vector<int> G[], int a, int b) { G[a].pb(b); G[b].pb(a); }
const int MAXN = 100005;
vector<int> G[MAXN];
vector<int> CV[MAXN/2];
int C[MAXN], Cn;
ll dp[MAXN], ds[MAXN];
bitset<MAXN> chk;
int A[MAXN], B[MAXN];
ll Ans;
int N;
void f(int i) {
for(int v : G[i]) {
f(v);
ds[i] += dp[v];
}
for(int v : G[i]) upmax(dp[i], ll(B[v]));
dp[i] += ds[i];
}
int main() {
ios::sync_with_stdio(false);
cin >> N;
for(int i = 1; i <= N; i++) cin >> A[i] >> B[i];
for(int i = 1; i <= N; i++) if(!chk[i]) {
vector<int> V;
int k = -1;
for(int j = i;;) {
chk[j] = true;
V.pb(j);
j = A[j];
if(chk[j]) {
k = j;
break;
}
}
int ki = -1;
for(int j = 0; j < sz(V); j++)
if(V[j] == k) ki = j;
if(ki < 0 || V.empty()) continue;
Cn++;
for(int j = ki; j < sz(V); j++) {
C[V[j]] = Cn;
CV[Cn].pb(V[j]);
}
}
if(1 == Cn && sz(CV[1]) == N) {
puts("0");
return 0;
}
for(int i = 1; i <= N; i++) {
if(C[i] && C[A[i]]) continue;
G[A[i]].pb(i);
}
for(int i = 1; i <= N; i++) if(C[i]) f(i);
for(int i = 1; i <= Cn; i++) {
vector<int> &V = CV[i];
const int n = sz(V);
ll ret = 0;
bool flag = false;
for(int j = 0; j < n; j++) {
ll a = dp[V[j]], b = ds[V[j]] + B[V[(j-1+n)%n]];
if(a >= b) {
ret += a;
flag = true;
} else {
ret += b;
}
}
if(flag) {
Ans += ret;
continue;
}
ll sum = ret; ret = 0;
for(int j = 0; j < n; j++)
upmax(ret, sum - ds[V[j]] - B[V[(j-1+n)%n]] + dp[V[j]]);
Ans += ret;
}
for(int i = 1; i <= N; i++) Ans -= B[i];
cout << (-Ans) << endl;
return 0;
}
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