# | Submission time | Handle | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
305551 | 2020-09-23T13:54:37 Z | AmineWeslati | Swapping Cities (APIO20_swap) | C++14 | 0 ms | 0 KB |
//Never stop trying #include "swap.h" #pragma GCC target ("avx2") #pragma GCC optimization ("O3") #pragma GCC optimization ("unroll-loops") #include <bits/stdc++.h> using namespace std; #define boost ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0) typedef string str; typedef long long ll; #define int ll typedef double db; typedef long double ld; typedef pair<int, int> pi; #define fi first #define se second typedef vector<int> vi; typedef vector<pi> vpi; typedef vector<str> vs; typedef vector<ld> vd; #define pb push_back #define sz(x) (int)x.size() #define all(x) begin(x), end(x) #define rall(x) rbegin(x), rend(x) #define endl "\n" #define FOR(i,a,b) for (int i = (a); i < (b); ++i) #define F0R(i,a) FOR(i,0,a) #define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i) #define R0F(i,a) ROF(i,0,a) const int MOD = 1e9 + 7; //998244353 const ll INF = 1e18; const int MX = 1e5 + 10; const int nx[4] = {0, 0, 1, -1}, ny[4] = {1, -1, 0, 0}; //right left down up template<class T> using V = vector<T>; template<class T> bool ckmin(T& a, const T& b) { return a > b ? a = b, 1 : 0; } template<class T> bool ckmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; } ll cdiv(ll a, ll b) { return a / b + ((a ^ b) > 0 && a % b); } // divide a by b rounded up constexpr int log2(int x) { return 31 - __builtin_clz(x); } // floor(log2(x)) #define dbg(x) cerr << " - " << #x << " : " << x << endl; #define dbgs(x,y) cerr << " - " << #x << " : " << x << " / " << #y << " : " << y << endl; #define dbgv(v) cerr << " - " << #v << " : " << endl << "[ "; for(auto it : v) cerr << it << ' '; cerr << ']' << endl; void IO() { #ifndef ONLINE_JUDGE freopen("input.txt", "r", stdin); freopen("output.txt", "w", stdout); #endif } int N,M; vpi adj[MX]; void init(int NN, int MM, vi U, vi V, vi W){ N=NN,M=MM; FOR(i,0,M){ adj[U[i]].pb({V[i],W[i]}); adj[V[i]].pb({U[i],W[i]}); } } int getMinimumFuelCapacity(int X, int Y) { if(N-1==M) return -1; return 0; } /* tree 5 4 1 2 1 1 3 1 2 4 1 2 5 1 */ /* Careful!!! .Array bounds .Infinite loops .Uninitialized variables / empty containers .Order of input Some insights: .Binary search .Graph representation .Write brute force code .Change your approach */