Submission #305170

#	Time	Username	Problem	Language	Result	Execution time	Memory
305170		Vimmer	Carnival Tickets (IOI20_tickets)	C++14	27 / 100	733 ms	51448 KiB

tickets

#include <bits/stdc++.h>
#include "tickets.h"
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>

#define N 1005
#define PB push_back
#define sz(x) int(x.size())
#define P 31
#define F first
#define M ll(1e9 + 7)
#define S second
#define all(x) x.begin(), x.end()
#define endl '\n'

//#pragma GCC optimize("unroll-loops")
//#pragma GCC optimize("-O3")
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize("fast-math")
//#pragma GCC optimize("no-stack-protector")

using namespace std;
//using namespace __gnu_pbds;

typedef long long ll;

//typedef tree<int, null_type, less_equal <int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;

ll mlt(ll a, ll b) {return (a * b) % M;}
ll sm(ll a, ll b) {return (a + b) % M;}

ll find_maximum(int k, vector<vector<int> > x)
{
    int n = sz(x);

    int m = sz(x[0]);

    vector <vector <int> > r;

    r.resize(n);

    pair <int, int> pos[n];

    for (int i = 0; i < n; i++)
    {
        pos[i] = {0, m - 1};

        r[i].resize(m, -1);
    }

    ll ans = 0;

    set <pair <int, int> > se; se.clear();

    for (int i = 0; i < n; i++)
        se.insert({x[i][0] + x[i][m - 1], i});

    for (int u = 0; u < k; u++)
    {
        set <pair <int, int> > st = se;

        se.clear();

        int i = 0;

        ll sum = 0;

        while (sz(st) > 0)
        {
            int nm = (*st.begin()).S;

            st.erase(st.begin());

            if (i < n / 2)
                sum -= x[nm][pos[nm].F++], r[nm][pos[nm].F - 1] = u;
                  else sum += x[nm][pos[nm].S--], r[nm][pos[nm].S + 1] = u;

            se.insert({x[nm][pos[nm].F] + x[nm][pos[nm].S], nm});

            i++;
        }

        ans += sum;
    }

    allocate_tickets(r);

    return ans;
}

• Subtask 1: 11 / 11
• Subtask 2: 16 / 16
• Subtask 3: 0 / 14
• Subtask 4: 0 / 14
• Subtask 5: 0 / 12
• Subtask 6: 0 / 23
• Subtask 7: 0 / 10