제출 #301810

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
301810		infinite_iq	슈퍼트리 잇기 (IOI20_supertrees)	C++14	46 / 100	265 ms	29048 KiB

supertrees

#include <bits/stdc++.h>
using namespace std ;
#define pb push_back 
#define C continue 
typedef vector < int > vi ;
typedef vector < vi > vivi ;
#include "supertrees.h"
vi v [100009] , comp ;
int col [100009] , P [100009] , timer ;
void dfs ( int node ) { 
        if ( col [node] ) return ;
        col [node] = timer ;
        comp .pb ( node ) ;
        for ( auto u : v [node] ) dfs ( u ) ;
}
int construct(std::vector<std::vector<int>> p) {
        int n = p.size();
        vivi ans ;
        for ( int i = 0 ; i < n ; i ++ ) {
                vi ret ( n , 0 ) ;
                ans .pb ( ret ) ;
        }
        for ( int i = 0 ; i < n ; i ++ ) {
                for ( int j = 0 ; j < n ; j ++ ) {
                        if ( p [i][j] == 1 ) {
                                v [i] .pb ( j ) ;
                        }
                }
        }
        for ( int i = 0 ; i < n ; i ++ ) {
                if ( col [i] ) C ;
                timer ++ ;
                comp .clear () ;
                dfs ( i ) ;
                P [timer] = comp [0] ;
                if ( comp .size () == 1 ) C ;
                for ( int j = 0 ; j < ( int ) comp .size () - 1 ; j ++ ) {
                        int a = comp [j] , b = comp [j+1] ;
                        ans [a][b] = ans [b][a] = 1 ;
                }
        }
        timer = 0 ;
        for ( int i = 0 ; i < n ; i ++ ) {
                v [i] .clear () ;
        }
        for ( int i = 0 ; i < n ; i ++ ) {
                for ( int j = 0 ; j < n ; j ++ ) {
                        if ( col [i] != col [j] && p [i][j] == 2 ) {
                                v [P[col[i]]] .pb (P[col[j]]) ;
                        }
                }
        }
        memset ( col , 0 , sizeof ( col ) ) ;
        for ( int i = 0 ; i < n ; i ++ ) {
                if ( col [i] ) C ;
                timer ++ ;
                comp .clear () ;
                dfs ( i ) ;
                if ( comp .size () == 1 ) C ;
                if ( comp .size () == 2 ) return 0 ;
                for ( int j = 0 ; j < ( int ) comp .size () - 1 ; j ++ ) {
                        int a = comp [j] , b = comp [j+1] ;
                        ans [a][b] = ans [b][a] = 1 ;
                }
                int a = comp [0] , b = comp .back () ;
                ans [a][b] = ans [b][a] = 1 ;
        }
        build ( ans ) ;
        return 1 ;
}

• Subtask 1: 11 / 11
• Subtask 2: 0 / 10
• Subtask 3: 0 / 19
• Subtask 4: 35 / 35
• Subtask 5: 0 / 21
• Subtask 6: 0 / 4