This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#include <prize.h>
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>
#define mp make_pair
#define pb push_back
#define all(a) (a).begin(), (a).end()
#define sz(a) a.size()
#define md(a, b) ((a) % b + b) % b
#define mod(a) md(a, MOD)
#define srt(a) sort(all(a))
#define mem(a, h) memset(a, (h), sizeof(a))
#define f first
#define s second
#define forn(i, n) for(int i = 0; i < n; i++)
#define fore(i, b, e) for(int i = b; i < e; i++)
#define forg(i, b, e, m) for(int i = b; i < e; i+=m)
//int in(){int r=0,c;for(c=getchar();c<=32;c=getchar());if(c=='-') return -in();for(;c>32;r=(r<<1)+(r<<3)+c-'0',c=getchar());return r;}
using namespace std;
//using namespace __gnu_pbds;
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
typedef pair<int, int> ii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef vector<ll> vll;
//typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update> ordered_set;
//find_by_order kth largest order_of_key <
const int tam = 100010;
const int MOD = 1000000007;
const int MOD1 = 998244353;
const double EPS = 1e-9;
const double PI = acos(-1);
/*int er[] = {4, 4, 4, 4, 3, 4, 4, 4, 4, 4, 2, 3, 4, 4, 4, 4, 4, 4, 4, 4, 3, 4, 4, 3, 1, 4, 4, 4, 4, 2, 4, 4, 4, 3};
vector<int> ar(100034);
int q;
int n;
vector<int> ask(int i)
{
q++;
vector<int> res(2, 0);
fore(j, 0, i)
res[0] += ar[j] < ar[i];
fore(j, i + 1, 100034)
res[1] += ar[j] < ar[i];
return res;
}
int find_best(int n);
int main()
{
q = 0;
fore(i, 0, 100000) ar[i] = 4;
fore(i, 100000, 100034) ar[i] = er[i - 100000];
cout<<find_best(100034)<<'\n';
cout<<q<<'\n';
return 0;
}*/
int find_best(int n)
{
int lo = 0, hi = n - 1, mid, res;
pair<int, pair<int, int>> maxi{0,{0, 0}};
int q = 0;
fore(i, 0, 475)
{
auto ar = ask(i);
q++;
if(ar[0] + ar[1] == 0)
return i;
if(ar[0] + ar[1] > 40)
{
maxi = mp(ar[0] + ar[1], mp(i, ar[0]));
break;
}
maxi = max(maxi, mp(ar[0] + ar[1], mp(i, ar[0])));
}
int can = maxi.f, pos = maxi.s.f, le = maxi.s.s;
//cout<<le<<'\n';
while(true)
{
//cout<<"sdac "<<pos<<'\n';
lo = pos + 1, hi = min(n - 1, pos + 1023), res = hi;
auto er = ask(hi);
q++;
if(er[0] + er[1] == 0)
return hi;
if(er[0] + er[1] != can || er[0] > le)
while(lo <= hi)
{
mid = (lo + hi) / 2;
auto ar = ask(mid);
q++;
//cout<<mid<<' '<<ar[0]<<' '<<ar[1]<<'\n';
if(ar[0] + ar[1] != can)
{
if(ar[0] + ar[1] == 0)
{
return -1;
return mid;
}
res = mid, hi = mid - 1;
}
else
{
if(ar[0] > le)
hi = mid - 1;
else
lo = mid + 1;
}
}
pos = res;
while(true)
{
auto ar = ask(pos);
q++;
if(ar[0] + ar[1] == 0)
{
return -1;
return pos;
}
if(ar[0] + ar[1] == can)
{
le = ar[0];
break;
}
pos++;
}
}
}
// read the question correctly (is y a vowel? what are the exact constraints?)
// look out for SPECIAL CASES (n=1?) and overflow (ll vs int?) ARRAY OUT OF BOUNDSS2
Compilation message (stderr)
prize.cpp: In function 'int find_best(int)':
prize.cpp:71:3: warning: this 'if' clause does not guard... [-Wmisleading-indentation]
71 | if(ar[0] + ar[1] == 0)
| ^~
prize.cpp:74:4: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'if'
74 | if(ar[0] + ar[1] > 40)
| ^~
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