oj.uz

답안 #300698

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
300698 2020-09-17T12:11:39 Z AmineWeslati 슈퍼트리 잇기 (IOI20_supertrees) C++14
46 / 100
 276 ms 30200 KB 
//Never stop trying
#include "supertrees.h"
#pragma GCC target ("avx2")
#pragma GCC optimization ("O3")
#pragma GCC optimization ("unroll-loops")
#include <bits/stdc++.h>
using namespace std;
#define boost ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)

typedef string str;
typedef long long ll;
//#define int ll
typedef double db;
typedef long double ld;
typedef pair<int, int> pi;
#define fi first
#define se second
typedef vector<int> vi;
typedef vector<pi> vpi;
typedef vector<str> vs;
typedef vector<ld> vd;
#define pb push_back
#define sz(x) (int)x.size()
#define all(x) begin(x), end(x)
#define rall(x) rbegin(x), rend(x)
#define endl "\n"

#define FOR(i,a,b) for (int i = (a); i < (b); ++i)
#define F0R(i,a) FOR(i,0,a)
#define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i)
#define R0F(i,a) ROF(i,0,a)

const int MOD = 1e9 + 7; //998244353
const ll INF = 1e18;
const int MX = 1001;
const int nx[4] = {0, 0, 1, -1}, ny[4] = {1, -1, 0, 0}; //right left down up

template<class T> using V = vector<T>;
template<class T> bool ckmin(T& a, const T& b) { return a > b ? a = b, 1 : 0; }
template<class T> bool ckmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; }

ll cdiv(ll a, ll b) { return a / b + ((a ^ b) > 0 && a % b); } // divide a by b rounded up
constexpr int log2(int x) { return 31 - __builtin_clz(x); } // floor(log2(x))

#define dbg(x) cerr << " - " << #x << " : " << x << endl;
#define dbgs(x,y) cerr << " - " << #x << " : " << x << " / " << #y << " : " << y << endl;
#define dbgv(v) cerr << " - " << #v << " : " << endl << "[ "; for(auto it : v) cerr << it << ' '; cerr << ']' << endl;

void IO() {
#ifndef ONLINE_JUDGE
	freopen("input.txt", "r", stdin);
	freopen("output.txt", "w", stdout);
#endif
}



int N;
int p[MX][MX];
vi adj[MX];
bool vis[MX]; set<int> s;

vi adj2[MX];
bool vis2[MX]; set<int> ss;



bool sub1(){
	FOR(i,0,N) FOR(j,0,N) if(p[i][j]!=1) return 0;
	return 1;
}

bool sub2(){
	FOR(i,0,N) FOR(j,i+1,N) if(i!=j) if(p[i][j]!=0 || p[i][j]!=1) return false;
	return true;
}
bool sub3(){
	FOR(i,0,N) FOR(j,i+1,N)if(i!=j) if(p[i][j]!=0 || p[i][j]!=2) return false;
	return true;
}


void dfs(int u){
	vis[u]=true;
	s.insert(u);
	for(auto v: adj[u]) if(!vis[v])dfs(v);
}
void dfs2(int u){
	vis2[u]=true;
	ss.insert(u);
	for(auto v: adj2[u]) if(!vis2[v])dfs2(v);
}

int construct(vector<vi> P) {
	N=sz(P[0]);
	vector<vi> res(N,vi(N,-1));
	FOR(i,0,N) FOR(j,0,N) p[i][j]=P[i][j],res[i][j]=0;

	if(sub1()){
		FOR(i,0,N-1) res[i][i+1]=res[i+1][i]=1;
	}
	else if(sub2()||sub3()){
		FOR(i,0,N) FOR(j,i+1,N) if(p[i][j]!=0){
			adj[i].pb(j); adj[j].pb(i);
		}
		FOR(i,0,N) vis[i]=false;
		FOR(i,0,N) if(!vis[i]){
			s.clear(); dfs(i);
			vi vec; for(auto x: s) vec.pb(x);
			if(sz(vec)==1) continue; //no edges to add
			//dbgv(vec);
			int cur=p[vec[0]][vec[1]];
			if(sz(vec)==2 && cur==2) return 0; //multiple edges
			FOR(j,0,sz(vec)) FOR(k,j+1,sz(vec)){
				if(p[vec[j]][vec[k]]!=cur) return 0;
			}
			FOR(i,0,sz(vec)){
				if(i<sz(vec)-1){
					res[vec[i]][vec[i+1]]=res[vec[i+1]][vec[i]]=1;
				}	
				if(i==sz(vec)-1 && cur==2) res[vec[i]][vec[0]]=res[vec[0]][vec[i]]=1;
			}
		}
	}
	else{
		FOR(i,0,N) FOR(j,i+1,N) if(p[i][j]!=0){
			adj[i].pb(j); adj[j].pb(i);
		}
		FOR(i,0,N) if(!vis[i]){
			s.clear(); dfs(i);
			vi vec; for(auto x: s) vec.pb(x);
			if(sz(vec)==1) continue; //no edges to add

			//We are in a connected component 
			
			FOR(j,0,sz(vec)) FOR(k,j+1,sz(vec)){
				if(p[vec[k]][vec[j]]==1){
					adj2[vec[k]].pb(vec[j]);
					adj2[vec[j]].pb(vec[k]);
				}
			}
			FOR(j,0,N) vis2[j]=false;

			vi cy;
			for(auto u: vec) if(!vis2[u]){
				ss.clear(); dfs2(u);
				vi vv; for(auto x: ss) vv.pb(x);
				cy.pb(u);
				if(sz(vv)==1) continue;
				FOR(i,0,sz(vv)-1){
					res[vv[i]][vv[i+1]]=res[vv[i+1]][vv[i]]=1;
				}
			}

			FOR(i,0,sz(cy)-1){
				res[cy[i]][cy[i+1]]=res[cy[i+1]][cy[i]]=1;
			}
			if(sz(cy)>1) res[cy.back()][cy[0]]=res[cy[0]][cy.back()]=1;

		}
	}

	build(res);

	return 1;
}

/*
5
0 0 0 0 0
0 0 2 2 2
0 2 0 2 2
0 2 2 0 2
0 2 2 2 0

0 0 0 0 0 
0 0 1 0 1 
0 1 0 1 0 
0 0 1 0 1 
0 1 0 1 0 
*/

/*
6
0 1 0 0 0 0
1 0 0 0 0 0
0 0 0 1 2 2
0 0 1 0 2 2
0 0 2 2 0 2
0 0 2 2 2 0

*/

/*
9
0 1 0 0 0 0 0 0 0
1 0 0 0 0 0 0 0 0
0 0 0 1 2 2 2 2 2
0 0 1 0 2 2 2 2 2
0 0 2 2 0 2 2 2 1
0 0 2 2 2 0 1 1 2
0 0 2 2 2 1 0 1 2
0 0 2 2 2 1 1 0 2
0 0 2 2 1 2 2 2 0


0 1 0 0 0 0 0 0 0 
1 0 0 0 0 0 0 0 0 
0 0 0 1 1 1 0 0 0 
0 0 1 0 0 0 0 0 0 
0 0 1 0 0 1 0 0 1 
0 0 1 0 1 0 1 0 0 
0 0 0 0 0 1 0 1 0 
0 0 0 0 0 0 1 0 0 
0 0 0 0 1 0 0 0 0 
*/




/* Careful!!!
	.Array bounds
	.Infinite loops
	.Uninitialized variables / empty containers
	.Order of input

   Some insights:
	.Binary search
	.Graph representation
	.Write brute force code
	.Change your approach
*/

Compilation message

supertrees.cpp:4: warning: ignoring #pragma GCC optimization [-Wunknown-pragmas]
    4 | #pragma GCC optimization ("O3")
      | 
supertrees.cpp:5: warning: ignoring #pragma GCC optimization [-Wunknown-pragmas]
    5 | #pragma GCC optimization ("unroll-loops")
      | 
supertrees.cpp: In function 'void IO()':
supertrees.cpp:51:9: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)', declared with attribute warn_unused_result [-Wunused-result]
   51 |  freopen("input.txt", "r", stdin);
      |  ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~
supertrees.cpp:52:9: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)', declared with attribute warn_unused_result [-Wunused-result]
   52 |  freopen("output.txt", "w", stdout);
      |  ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~

Subtask #1
11.0 / 11.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 384 KB Output is correct
2 Correct 1 ms 384 KB Output is correct
3 Correct 1 ms 384 KB Output is correct
4 Correct 1 ms 384 KB Output is correct
5 Correct 1 ms 384 KB Output is correct
6 Correct 11 ms 2048 KB Output is correct
7 Correct 266 ms 26104 KB Output is correct

Subtask #2
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 384 KB Output is correct
2 Correct 1 ms 384 KB Output is correct
3 Correct 1 ms 384 KB Output is correct
4 Correct 1 ms 384 KB Output is correct
5 Correct 1 ms 384 KB Output is correct
6 Correct 11 ms 2048 KB Output is correct
7 Correct 266 ms 26104 KB Output is correct
8 Correct 1 ms 384 KB Output is correct
9 Correct 1 ms 384 KB Output is correct
10 Correct 0 ms 384 KB Output is correct
11 Correct 1 ms 384 KB Output is correct
12 Correct 11 ms 2048 KB Output is correct
13 Correct 258 ms 26236 KB Output is correct
14 Incorrect 1 ms 384 KB Answer gives possible 1 while actual possible 0
15 Halted 0 ms 0 KB -

Subtask #3
0 / 19.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 384 KB Output is correct
2 Correct 1 ms 384 KB Output is correct
3 Correct 1 ms 384 KB Output is correct
4 Incorrect 1 ms 384 KB Answer gives possible 1 while actual possible 0
5 Halted 0 ms 0 KB -

Subtask #4
35.0 / 35.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 384 KB Output is correct
2 Correct 1 ms 384 KB Output is correct
3 Correct 1 ms 384 KB Output is correct
4 Correct 66 ms 8056 KB Output is correct
5 Correct 264 ms 27168 KB Output is correct
6 Correct 264 ms 26172 KB Output is correct
7 Correct 276 ms 30200 KB Output is correct
8 Correct 1 ms 384 KB Output is correct
9 Correct 70 ms 7928 KB Output is correct
10 Correct 265 ms 26616 KB Output is correct
11 Correct 262 ms 26104 KB Output is correct
12 Correct 273 ms 29176 KB Output is correct
13 Correct 1 ms 384 KB Output is correct
14 Correct 1 ms 384 KB Output is correct
15 Correct 1 ms 384 KB Output is correct
16 Correct 64 ms 7804 KB Output is correct
17 Correct 262 ms 26636 KB Output is correct
18 Correct 260 ms 26616 KB Output is correct
19 Correct 257 ms 26492 KB Output is correct
20 Correct 258 ms 26104 KB Output is correct

Subtask #5
0 / 21.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 384 KB Output is correct
2 Correct 1 ms 384 KB Output is correct
3 Correct 1 ms 384 KB Output is correct
4 Correct 1 ms 384 KB Output is correct
5 Correct 1 ms 384 KB Output is correct
6 Correct 11 ms 2048 KB Output is correct
7 Correct 266 ms 26104 KB Output is correct
8 Correct 1 ms 384 KB Output is correct
9 Correct 1 ms 384 KB Output is correct
10 Correct 0 ms 384 KB Output is correct
11 Correct 1 ms 384 KB Output is correct
12 Correct 11 ms 2048 KB Output is correct
13 Correct 258 ms 26236 KB Output is correct
14 Incorrect 1 ms 384 KB Answer gives possible 1 while actual possible 0
15 Halted 0 ms 0 KB -

Subtask #6
0 / 4.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 384 KB Output is correct
2 Correct 1 ms 384 KB Output is correct
3 Correct 1 ms 384 KB Output is correct
4 Correct 1 ms 384 KB Output is correct
5 Correct 1 ms 384 KB Output is correct
6 Correct 11 ms 2048 KB Output is correct
7 Correct 266 ms 26104 KB Output is correct
8 Correct 1 ms 384 KB Output is correct
9 Correct 1 ms 384 KB Output is correct
10 Correct 0 ms 384 KB Output is correct
11 Correct 1 ms 384 KB Output is correct
12 Correct 11 ms 2048 KB Output is correct
13 Correct 258 ms 26236 KB Output is correct
14 Incorrect 1 ms 384 KB Answer gives possible 1 while actual possible 0
15 Halted 0 ms 0 KB -