This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "rect.h"
#include <bits/stdc++.h>
using namespace std;
#define m_p make_pair
#define fi first
#define se second
#define all(x) (x).begin(),(x).end()
#define sz(x) ((int)(x).size())
typedef long long ll;
const int N = 2505;
const int xx[4] = {1, 0, -1, 0};
const int yy[4] = {0, 1, 0, -1};
int n, m;
int a[N][N];
bool c[N][N];
int q;
int minx, maxx, miny, maxy;
void dfs(int x, int y)
{
c[x][y] = true;
++q;
minx = min(minx, x);
maxx = max(maxx, x);
miny = min(miny, y);
maxy = max(maxy, y);
for (int i = 0; i < 4; ++i)
{
int hx = x + xx[i];
int hy = y + yy[i];
if (hx >= 1 && hx <= n && hy >= 1 && hy <= m && !c[hx][hy] && a[hx][hy] == 0)
{
dfs(hx, hy);
}
}
}
ll solv6()
{
ll ans = 0;
for (int x = 1; x <= n; ++x)
{
for (int y = 1; y <= m; ++y)
{
if (a[x][y] == 0)
{
if (!c[x][y])
{
q = 0;
minx = maxx = x;
miny = maxy = y;
dfs(x, y);
if (minx == 1 || maxx == n)
continue;
if (miny == 1 || maxy == m)
continue;
if ((maxx - minx + 1) * (maxy - miny + 1) == q)
{
++ans;
}
}
}
}
}
return ans;
}
int l[N][N], r[N][N];
int maxu[N];
int ul[N], ur[N];
long long count_rectangles(std::vector<std::vector<int> > A)
{
n = sz(A);
m = sz(A[0]);
for (int i = 1; i <= n; ++i)
{
for (int j = 1; j <= m; ++j)
{
a[i][j] = A[i - 1][j - 1];
}
}
bool z = true;
for (int i = 1; i <= n; ++i)
{
for (int j = 1; j <= m; ++j)
{
if (a[i][j] > 1)
{
z = false;
}
}
}
if (z)
{
return solv6();
}
for (int i = 1; i <= n; ++i)
{
for (int j = 1; j <= m; ++j)
{
l[i][j] = j;
while (l[i][j] > 1 && a[i][j] > a[i][l[i][j] - 1])
--l[i][j];
r[i][j] = j;
while (r[i][j] < m && a[i][j] > a[i][r[i][j] + 1])
++r[i][j];
}
}
ll ans = 0;
for (int x1 = 2; x1 < n; ++x1)
{
for (int x2 = x1; x2 < n; ++x2)
{
for (int y = 1; y <= m; ++y)
{
if (x2 == x1)
{
maxu[y] = a[x2][y];
ul[y] = l[x2][y];
ur[y] = r[x2][y];
}
else
{
maxu[y] = max(maxu[y], a[x2][y]);
ul[y] = max(ul[y], l[x2][y]);
ur[y] = min(ur[y], r[x2][y]);
}
}
for (int y1_ = 2; y1_ < m; ++y1_)
{
for (int y2 = y1_; y2 < m; ++y2)
{
if (maxu[y2] >= a[x1 - 1][y2])
break;
if (maxu[y2] >= a[x2 + 1][y2])
break;
if (ur[y1_ - 1] >= y2 && ul[y2 + 1] <= y1_)
++ans;
}
}
}
}
return ans;
}
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