답안 #293257

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
293257 2020-09-07T19:58:22 Z AmineWeslati Furniture (JOI20_furniture) C++14
0 / 100
3 ms 2048 KB
//Never stop trying

#include <bits/stdc++.h>
using namespace std;
#define boost ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)

typedef string str;
typedef long long ll;
#define int ll
typedef double db;
typedef long double ld;
typedef pair<int, int> pi;
#define fi first
#define se second
typedef vector<int> vi;
typedef vector<pi> vpi;
typedef vector<str> vs;
typedef vector<ld> vd;
#define pb push_back
#define sz(x) (int)x.size()
#define all(x) begin(x), end(x)
#define rall(x) rbegin(x), rend(x)
#define endl "\n"

#define FOR(i,a,b) for (int i = (a); i < (b); ++i)
#define F0R(i,a) FOR(i,0,a)
#define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i)
#define R0F(i,a) ROF(i,0,a)

const int MOD = 1e9 + 7; //998244353
const ll INF = 1e18;
const int MX = 2e5 + 10;
const int nx[4] = {0, 0, 1, -1}, ny[4] = {1, -1, 0, 0}; //right left down up

template<class T> using V = vector<T>;
template<class T> bool ckmin(T& a, const T& b) { return a > b ? a = b, 1 : 0; }
template<class T> bool ckmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; }

ll cdiv(ll a, ll b) { return a / b + ((a ^ b) > 0 && a % b); } // divide a by b rounded up
constexpr int log2(int x) { return 31 - __builtin_clz(x); } // floor(log2(x))

#define dbg(x) cerr << " - " << #x << " : " << x << endl;
#define dbgs(x,y) cerr << " - " << #x << " : " << x << " / " << #y << " : " << y << endl;
#define dbgv(v) cerr << " - " << #v << " : " << endl << "[ "; for(auto it : v) cerr << it << ' '; cerr << ']' << endl;

void IO() {
#ifndef ONLINE_JUDGE
	freopen("input.txt", "r", stdin);
	freopen("output.txt", "w", stdout);
#endif
}

int N,M;
int g[1001][1001];

int A[1000][1000];
int B[1000][1000];
int memo[1000][1000];

int solve(int x, int y){
	if(x<0|| y<0 || x>=N || y>=M || g[x][y]==1) return 0;
	if(x==N-1 && y==M-1) return 1;
	if(memo[x][y]!=-1) return memo[x][y];
	return memo[x][y] = (solve(x,y+1)+solve(x+1,y))%MOD; 
}

int solve2(int x, int y){
	//cout << x << ' ' << y << endl;
	if(x<0|| y<0 || x>=N || y>=M || g[x][y]==1) return 0;
	if(x==0 && y==0) return 1;
	if(memo[x][y]!=-1) return memo[x][y]; 
	
	
	int xx=(solve2(x,y-1)+solve2(x-1,y))%MOD; 
	//if(x==0 && y==1) cout << xx << endl;
	return memo[x][y] =  xx;

}

int32_t main() {
	boost; 

	cin>>N>>M;
	FOR(i,0,N) FOR(j,0,M) cin>>g[i][j];

	FOR(i,0,N) FOR(j,0,M) memo[i][j]=-1;
	FOR(i,0,N) FOR(j,0,M) A[i][j]=solve(i,j);
	FOR(i,0,N) FOR(j,0,M) memo[i][j]=-1;
	FOR(i,0,N) FOR(j,0,M) B[i][j]=solve2(i,j);

	//FOR(i,0,N){FOR(j,0,M) cout << B[i][j] << ' '; cout << endl;}


	int X=A[0][0];
	FOR(i,0,N) FOR(j,0,M) A[i][j]*=B[i][j];

	//FOR(i,0,N){FOR(j,0,M) cout << A[i][j] << ' '; cout << endl;}

	int Q; cin>>Q;
	
	while(Q--){
		int x,y; cin>>x>>y; x--; y--;
		int nb=A[x][y];
		//cout << X << ' ' << nb << endl; 
		if((((X-nb)%MOD+MOD)%MOD)==0) cout << 0 << endl;
		else{
			cout << 1 << endl;
			X-=nb; X%=MOD; X+=MOD; X%=MOD;
		}
	}


	return 0;
}

/* Careful!!!
	.Array bounds
	.Infinite loops
	.Uninitialized variables / empty containers
	.Order of input

   Some insights:
	.Binary search
	.Graph representation
	.Write brute force code
	.Change your approach
*/

Compilation message

furniture.cpp: In function 'void IO()':
furniture.cpp:48:9: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)', declared with attribute warn_unused_result [-Wunused-result]
   48 |  freopen("input.txt", "r", stdin);
      |  ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~
furniture.cpp:49:9: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)', declared with attribute warn_unused_result [-Wunused-result]
   49 |  freopen("output.txt", "w", stdout);
      |  ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~
# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 1664 KB Output is correct
2 Incorrect 3 ms 2048 KB Output isn't correct
3 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 1664 KB Output is correct
2 Incorrect 3 ms 2048 KB Output isn't correct
3 Halted 0 ms 0 KB -