Submission #292789

#	Time	Username	Problem	Language	Result	Execution time	Memory
292789		b00n0rp	Furniture (JOI20_furniture)	C++17	100 / 100	535 ms	41836 KiB

furniture

/*
Soln:
Keep track of up/down/lft/rgt[i][j]. 
up[i][j] stores whether there is a path from 1,1 to i-1,j to i,j
and the rest can be defined so as well
If we know for a fact that blocking i,j won't block the path we can just recursively change
up/down/lft/rgt[i][j].
This will be O(nm) over all queries
To check whether blocking i,j will block the path we can run a O(n+m) loop per query
or we can use segtrees/BITs to make it O(log(n)+log(m)) per query
Test cases are weak so O((n+m)) per query or O(nm*(n+m)) in total also works
*/

// --------------------------------------------------<TEMPLATE>--------------------------------------------------
// --------------------<optimizations>--------------------
/*
#pragma GCC optimize("Ofast,unroll-loops")
#pragma GCC target("avx,avx2,fma")
*/ 
// -------------------</optimizations>--------------------
 
// ---------------<Headers and namespaces>----------------
#include <bits/stdc++.h>
using namespace std;
 
/*
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
*/
 
// ---------------</Headers and namespaces>---------------
 
// -----------------<Defines and typedefs>----------------
// typedef tree<int,null_type,less<int>,rb_tree_tag, 
// tree_order_statistics_node_update> indexed_set; // use less_equal for multiset
// order_of_key (val): returns the no. of values less than val
// find_by_order (k): returns the iterator to kth largest element.(0-based)
 
typedef long double LD;
typedef long long ll;
#define int ll
#define pb push_back
#define mp make_pair
#define REP(i,n) for (int i = 0; i < n; i++)
#define FOR(i,a,b) for (int i = a; i < b; i++)
#define REPD(i,n) for (int i = n-1; i >= 0; i--)
#define FORD(i,a,b) for (int i = a; i >= b; i--)
#define remax(a,b) a = max(a,b)
#define remin(a,b) a = min(a,b)
#define all(v) v.begin(),v.end()
typedef map<int,int> mii;
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef pair<int,int> pii;
typedef vector<pii> vpii;
#define F first
#define S second
#define PQ(type) priority_queue<type>
#define PQD(type) priority_queue<type,vector<type>,greater<type> >
#define WL(t) while(t --)
#define SZ(x) ((int)(x).size())
#define runtime() ((double)clock() / CLOCKS_PER_SEC)
#define inrange(i,a,b) ((i>=min(a,b)) && (i<=max(a,b)))
 
/*
// -----<SCANF>-----
#define sfi(x) scanf("%d",&x);
#define sfi2(x,y) scanf("%d%d",&x,&y);
#define sfi3(x,y,z) scanf("%d%d%d",&x,&y,&z);
 
#define sfl(x) scanf("%lld",&x);
#define sfl2(x,y) scanf("%lld%lld",&x,&y);
#define sfl3(x,y,z) scanf("%lld%lld%lld",&x,&y,&z);
#define sfl4(x,y,z,x1) scanf("%lld%lld%lld%lld",&x,&y,&z,&x1);
#define sfl5(x,y,z,x1,y1) scanf("%lld%lld%lld%lld%lld",&x,&y,&z,&x1,&y1);
#define sfl6(x,y,z,x1,y1,z1) scanf("%lld%lld%lld%lld%lld%lld",&x,&y,&z,&x1,&y1,&z1);
 
#define sfs(x) scanf("%s",x);
#define sfs2(x,y) scanf("%s%s",x,y);
#define sfs3(x,y,z) scanf("%s%s%s",x,y,z);
// ----</SCANF>-----
 
// ----<PRINTF>-----
#define pfi(x) printf("%d\n",x);
#define pfi2(x,y) printf("%d %d\n",x,y);
#define pfi3(x,y,z) printf("%d %d %d\n",x,y,z);
 
#define pfl(x) printf("%lld\n",x);
#define pfl2(x,y) printf("%lld %lld\n",x,y);
#define pfl3(x,y,z) printf("%lld %lld %lld\n",x,y,z);
 
#define pfs(x) printf("%s\n",x);
#define pfs2(x,y) printf("%s %s\n",x,y);
#define pfs3(x,y,z) printf("%s %s %s\n",x,y,z);
 
#define pwe(x) printf("%lld ",x); // print without end
// ----</PRINTF>----
*/
#define FLSH fflush(stdout)
#define fileIO(name) \
    freopen(name".in", "r", stdin); \
    freopen(name".out", "w", stdout);
#define PRECISION(x) cout << fixed << setprecision(x); 
#define FAST_IO ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
 
// ----------------</Defines and typedefs>----------------
 
// -------------------<Debugging stuff>-------------------
#ifdef TRACE
#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)
template <typename Arg1>
void __f(const char* name, Arg1&& arg1){
    cout << name << " : " << arg1 << std::endl;
}
template <typename Arg1, typename... Args>
void __f(const char* names, Arg1&& arg1, Args&&... args){
    const char* comma = strchr(names + 1, ',');cout.write(names, comma - names) << " : " << arg1<<" | ";__f(comma+1, args...);
}
#else
#define trace(...)
#endif
 
// ------------------</Debugging stuff>-------------------
 
// ------------------------<Consts>-----------------------
const int MAXN = 1005;
const int SQRTN = 1003;
const int LOGN = 22;
const double PI=acos(-1);
 
#ifdef int
const int INF=1e16;
#else
const int INF=1e9;
#endif
 
const int MOD = 1000000007;
const int FMOD = 998244353;
const double eps = 1e-9;
// -----------------------</Consts>-----------------------
/*
// -------------------------<RNG>-------------------------
mt19937 RNG(chrono::steady_clock::now().time_since_epoch().count()); 
#define SHUF(v) shuffle(all(v), RNG);
// Use mt19937_64 for 64 bit random numbers.
 
// ------------------------</RNG>-------------------------
 
// ----------------------<MATH>---------------------------
template<typename T> T gcd(T a, T b){return(b?__gcd(a,b):a);}
template<typename T> T lcm(T a, T b){return(a*(b/gcd(a,b)));}
int add(int a, int b, int c = MOD){int res=a+b;return(res>=c?res-c:res);}
int mod_neg(int a, int b, int c = MOD){int res;if(abs(a-b)<c)res=a-b;else res=(a-b)%c;return(res<0?res+c:res);}
int mul(int a, int b, int c = MOD){ll res=(ll)a*b;return(res>=c?res%c:res);}
int muln(int a, int b, int c = MOD){ll res=(ll)a*b;return ((res%c)+c)%c;}
ll mulmod(ll a,ll b, ll m = MOD){ll q = (ll)(((LD)a*(LD)b)/(LD)m);ll r=a*b-q*m;if(r>m)r%=m;if(r<0)r+=m;return r;}
template<typename T>T expo(T e, T n){T x=1,p=e;while(n){if(n&1)x=x*p;p=p*p;n>>=1;}return x;}
template<typename T>T power(T e, T n, T m = MOD){T x=1,p=e;while(n){if(n&1)x=mul(x,p,m);p=mul(p,p,m);n>>=1;}return x;}
template<typename T>T extended_euclid(T a, T b, T &x, T &y){T xx=0,yy=1;y=0;x=1;while(b){T q=a/b,t=b;b=a%b;a=t;\
t=xx;xx=x-q*xx;x=t;t=yy;yy=y-q*yy;y=t;}return a;}
template<typename T>T mod_inverse(T a, T n = MOD){T x,y,z=0;T d=extended_euclid(a,n,x,y);return(d>1?-1:mod_neg(x,z,n));}
 
const int FACSZ = 1; // Make sure to change this
 
int fact[FACSZ],ifact[FACSZ];
 
void precom(int c = MOD){
    fact[0] = 1;
    FOR(i,1,FACSZ) fact[i] = mul(fact[i-1],i,c);
    ifact[FACSZ-1] = mod_inverse(fact[FACSZ-1],c);
    REPD(i,FACSZ-1){
        ifact[i] = mul(i+1,ifact[i+1],c);
    }
}
 
int ncr(int n,int r,int c = MOD){
    return mul(mul(ifact[r],ifact[n-r],c),fact[n],c);
} 
*/
// ----------------------</MATH>--------------------------
// --------------------------------------------------</TEMPLATE>--------------------------------------------------
 
void solvethetestcase();
 
signed main(){
    // comment when using scanf,printf
    FAST_IO
    int t = 1;
    // (UNCOMMENT FOR MULTIPLE TEST CASES)
    // cin >> t;
    FOR(testcase,1,t+1){
        // (UNCOMMENT FOR CODEJAM)
        // printf("Case #%lld: ",testcase); 
        solvethetestcase();
    }
}   
 
int n,m,q;
int a[MAXN][MAXN];
int up[MAXN][MAXN],down[MAXN][MAXN],lft[MAXN][MAXN],rgt[MAXN][MAXN];

void recurse(int x,int y){
    up[x][y] = 0;
    down[x][y] = 0;
    lft[x][y] = 0;
    rgt[x][y] = 0;

    if(rgt[x][y-1]){
        rgt[x][y-1] = 0;
        if(!down[x][y-1]) recurse(x,y-1);
    }
    if(lft[x][y+1]){
        lft[x][y+1] = 0;
        if(!up[x][y+1]) recurse(x,y+1);
    }
    if(down[x-1][y]){
        down[x-1][y] = 0;
        if(!rgt[x-1][y]) recurse(x-1,y);
    }
    if(up[x+1][y]){
        up[x+1][y] = 0;
        if(!lft[x+1][y]) recurse(x+1,y);
    }
}

int query(int x,int y){
    if(up[x][y] == 0 and down[x][y] == 0 and lft[x][y] == 0 and rgt[x][y] == 0) return 1;
    bool f0 = 1,f1 = 1;
    FOR(i,x+1,n+1){
        if(lft[i][y]){
            f0 = 0;
            break;
        }
    }
    if(f0)
    FOR(j,y+1,m+1){
        if(up[x][j]){
            f0 = 0;
            break;
        }
    }
    FOR(i,1,x){
        if(rgt[i][y]){
            f1 = 0;
            break;
        }
    }
    if(f1)
    FOR(j,1,y){
        if(down[x][j]){
            f1 = 0;
            break;
        }
    }
    if(f0 or f1) return 0;
    recurse(x,y);
    return 1;
}
 
void solvethetestcase(){
    cin >> n >> m;
    FOR(i,1,n+1){
        FOR(j,1,m+1){
            cin >> a[i][j];
        }
    }
    FOR(i,1,n+1){
        FOR(j,1,m+1){
            if(i == 1 and j == 1){
                up[i][j] = 1;
                down[i][j] = 1;
                lft[i][j] = 1;
                rgt[i][j] = 1;
                continue;
            }
            up[i][j] = (i > 1);
            down[i][j] = (i < n);
            lft[i][j] = (j > 1);
            rgt[i][j] = (j < m);
        }
    }
    FOR(i,1,n+1){
        FOR(j,1,m+1){
            if(a[i][j]) recurse(i,j);
        }
    }
    cin >> q;
    REP(xyz,q){
        int x,y; cin >> x >> y;
        cout << query(x,y) << "\n";
    }
}

• Subtask 1: 5 / 5
• Subtask 2: 95 / 95