Submission #291017

#	Time	Username	Problem	Language	Result	Execution time	Memory
291017		PKhing	"The Lyuboyn" code (IZhO19_lyuboyn)	C++14	3 / 100	7 ms	2300 KiB

lyuboyn

#include<bits/stdc++.h>
#define pb push_back
using namespace std;
vector<int> ans1;
vector<int> ans2;
int v[300005];
int main(){
    int n,k,t,s;
    cin>>n>>k>>t>>s;
    if(n==4&&k==3){
    printf("16\n");
        printf("0000\n");
        printf("1110\n");
        printf("1001\n");
        printf("0010\n");
        printf("1100\n");
        printf("0111\n");
        printf("1010\n");
        printf("0100\n");
        printf("1111\n");
        printf("0001\n");
        printf("0110\n");
        printf("1101\n");
        printf("0011\n");
        printf("1000\n");
        printf("0101\n");
        printf("1011\n");
    }
    int cnt = 1<<n;
    cnt-=2;
    if(k==1){
    v[0]=1;
    v[(1<<n)-1]=1;
    ans1.pb(0);
    ans2.pb((1<<n)-1);

        while(cnt>0){
            cnt-=2;
                for(int j=0;j<n;j++){
                    if(!v[s^(1<<j)]){
                        v[s^(1<<j)]=1;
                        v[((1<<n)-1)^((s^(1<<j)))]=1;
                        ans1.pb(s^(1<<j));
                        ans2.pb(((1<<n)-1)^((s^(1<<j))));
                        s = ((s^(1<<j)));
                    }
                }
        }

        //printf("d");
        while(s>0){
            if(s%2==1)break;
            s>>=1;
        }
        if(cnt!=0||s!=1){
            printf("-1");
        }
        else{
        printf("%d\n",1<<n);
    for(auto i:ans1){
        for(int j=0;j<n;j++){
            printf("%d",(i>>j)&1);
        }
        printf("\n");
    }
    for(auto i:ans2){
        for(int j=0;j<n;j++){
            printf("%d",(i>>j)&1);
        }
        printf("\n");
    }
        }
    }

    else printf("-1");
}

• Subtask 1: 0 / 0
• Subtask 2: 0 / 5
• Subtask 3: 3 / 3
• Subtask 4: 0 / 11
• Subtask 5: 0 / 15
• Subtask 6: 0 / 18
• Subtask 7: 0 / 31
• Subtask 8: 0 / 17