Submission #290259

#TimeUsernameProblemLanguageResultExecution timeMemory
290259amoo_safarAliens (IOI16_aliens)C++17
41 / 100
1133 ms4588 KiB
#include "aliens.h" #include <bits/stdc++.h> #define F first #define S second #define pb push_back #define all(x) x.begin(), x.end() #define debug(x) cerr << #x << " : " << x << '\n'; using namespace std; typedef long long ll; typedef pair<int, int> pii; typedef pair<ll, ll> pll; const ll Inf = 1e18; const int N = 4e3 + 10; const int K = N; vector<ll> R, C; int n, m, k; pll dp[N]; ll Dup[N]; void Prep(){ ll r, c; for(int i = 1; i < m; i++){ r = R[i]; c = C[i - 1]; if(c > r) Dup[i] = (c - r) * (c - r); } //debug(Dup[1]); } /* void SolveN2K(){ memset(dp, 31, sizeof dp); dp[0][1] = (C[0] - R[0]) * (C[0] - R[0]); for(int i = 1; i < m; i++){ for(int j = 1; j <= i + 1; j++){ for(int la = 1; la <= i; la ++){ dp[i][j] = min(dp[i][j], dp[la - 1][j - 1] - Dup[la] + (C[i] - R[la]) * (C[i] - R[la])); } } dp[i][1] = min(dp[i][1], (C[i] - R[0]) * (C[i] - R[0])); } } */ pll CheckN2(ll cost){ fill(dp, dp + N , pll(Inf, Inf)); dp[0] = {(C[0] - R[0]) * (C[0] - R[0]) + cost, 1}; for(int i = 1; i < m; i++){ for(int la = 1; la <= i; la ++){ dp[i] = min(dp[i], {dp[la - 1].F - Dup[la] + (C[i] - R[la]) * (C[i] - R[la]) + cost, dp[la - 1].S + 1}); } dp[i] = min(dp[i], {(C[i] - R[0]) * (C[i] - R[0]) + cost, 1}); } return dp[m - 1]; } ll SolveN2LG(){ if(k == 1){ return (C[m - 1] - R[0]) * (C[m - 1] - R[0]); } if(k == m){ ll ans = 0; for(int i = 0; i < m; i++){ ans += (C[i] - R[i]) * (C[i] - R[i]) - Dup[i]; } return ans; } ll L = 0, R = 1e12, mid; while(L + 1 < R){ mid = (L + R) >> 1; if(CheckN2(mid).S <= k) R = mid; else L = mid; } pll res = CheckN2(R); //pll res2 = CheckN2(L); //if(res2.S == k) //return res2.F - res2.S * L; ll ans = res.F - res.S * R; ans -= R * (k - res.S); return ans; } ll take_photos(int _m, int _n, int _k, vector<int> _r, vector<int> _c) { n = _n; k = _k; for(int i = 0; i < _m; i++) if(_r[i] > _c[i]) swap(_r[i], _c[i]); vector<int> I(_m); iota(all(I), 0); sort(all(I), [&](int i, int j){ return pii(_r[i], -_c[i]) < pii(_r[j], -_c[j]); }); int mx = -1; for(int i : I){ if(_c[i] > mx){ mx = _c[i]; R.pb(_r[i]); C.pb(_c[i] + 1); } } m = R.size(); ll ans = Inf; //cerr << "! " << m << '\n'; //for(int i = 0; i < m; i++) cerr << R[i] << ' ' << C[i] << '\n'; Prep(); //SolveN2K(); k = min(k, m); //for(int i = 1; i <= k; i++) ans = min(ans, dp[m - 1][i]); ans = SolveN2LG(); return ans; }
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