Submission #278108

#	Time	Username	Problem	Language	Result	Execution time	Memory
278108		amiratou	Gondola (IOI14_gondola)	C++14	75 / 100	27 ms	3800 KiB

gondola

#include "gondola.h"
#include <bits/stdc++.h>
using namespace std;
#define sz(x) (int)(x.size())
const int MOD =(int)(1e9+9);
typedef long long ll;
int val[100005],here[250005],p[250005],dp[100005][2];

int valid(int n, int inputSeq[])
{
	int idx=-1;
	for (int i = 0; i < n; ++i){
		if(here[inputSeq[i]])return 0;
		here[inputSeq[i]]=1;
		if(inputSeq[i]<=n)idx=i;
	}
	if(idx==-1)return 1;
	int h=inputSeq[idx];
	for (int i = 0; i < n; ++i)
		val[(idx+i)%n]=((h-1+i)%n)+1;
	for (int i = 0; i < n; ++i)
		if(inputSeq[i]<=n && inputSeq[i]!=val[i])return 0;
	return 1;
}

//----------------------

int replacement(int n, int gondolaSeq[], int replacementSeq[])
{
	memset(here,-1,sizeof here);
	int flag=-1;
	for (int i = 0; i < n; ++i){
		if(gondolaSeq[i]<=n)flag=i;
		else here[gondolaSeq[i]]=i;
	}
	priority_queue<int,vector<int>,greater<int> > pq;
	if(flag!=-1){
		int g=gondolaSeq[flag];
		for (int i = 0; i < n; ++i){
			int r=((g-1+i)%n)+1;
			if(gondolaSeq[(flag+i)%n]!=r)pq.push(gondolaSeq[(flag+i)%n]),p[gondolaSeq[(flag+i)%n]]=r;
		}
	}
	else{
		for (int i = 0; i < n; ++i)
			p[gondolaSeq[i]]=i+1,pq.push(gondolaSeq[i]);
	}
	int h=n+1,idx=0;
	while(!pq.empty()){
		int f=pq.top();
		pq.pop();
		replacementSeq[idx++]=p[f];
		while(h<f)replacementSeq[idx++]=h++;
		h++;
	}
	return idx;
}

//----------------------
int binpow(int a,int b){
	if(!b)return 1;
	ll h=binpow(a,b>>1);
	h*=h;
	if(h>=MOD)h%=MOD;
	if(b&1)h*=a;
	if(h>=MOD)h%=MOD;
	return (int)(h);
}

int countReplacement(int n, int inputSeq[])
{
	if(!valid(n,inputSeq))return 0;
	int idx=-1;
	for (int i = 0; i < n; ++i)
		if(inputSeq[i]<=n)idx=i;
	if(idx==-1)return 1;
	int h=inputSeq[idx];
	for (int i = 0; i < n; ++i)
		val[(idx+i)%n]=((h-1+i)%n)+1;
	vector<int> vec={n};
	for (int i = 0; i < n; ++i)
		if(inputSeq[i]>n)
			vec.push_back(inputSeq[i]);
	ll ans=1;
	sort(vec.begin(),vec.end());
	for (int i = 1; i < sz(vec); ++i)
		ans=(ans*binpow(sz(vec)-i,vec[i]-vec[i-1]-1))%MOD;
	return ans;
}

• Subtask 1: 5 / 5
• Subtask 2: 5 / 5
• Subtask 3: 10 / 10
• Subtask 4: 5 / 5
• Subtask 5: 10 / 10
• Subtask 6: 20 / 20
• Subtask 7: 5 / 5
• Subtask 8: 15 / 15
• Subtask 9: 0 / 15
• Subtask 10: 0 / 10