# | Submission time | Handle | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
277478 | 2020-08-21T05:18:17 Z | 문홍윤(#5120) | Travelling Salesperson (CCO20_day2problem1) | C++17 | 2 ms | 512 KB |
#include <bits/stdc++.h> #define eb emplace_back #define mp make_pair #define F first #define S second #define all(x) x.begin(), x.end() #define svec(x) sort(x.begin(), x.end()) #define press(x) x.erase(unique(x.begin(), x.end()), x.end()) using namespace std; typedef long long LL; typedef pair<int, int> pii; typedef pair<LL, LL> pll; typedef pair<int, LL> pil; typedef pair<LL, int> pli; const LL llinf=2e18; const int inf=1e9; char str[2010][2010]; int n; void solve(int st){ vector<int> r, b; r.eb(st); b.eb(st); for(int i=1; i<=n; i++){ if(i==st)continue; int ch=r.back(); if(str[ch][i]=='R'){ b.pop_back(); if(!b.size()){ if(ch==st){ reverse(all(r)); ch=r.back(); b.eb(ch); if(str[ch][i]=='R'){ b.pop_back(); r.eb(i); b.eb(i); } else{ r.pop_back(); r.eb(i); b.eb(i); } } else{ r.eb(i); b.eb(i); } } else{ if(str[i][b.back()]=='B'){ r.eb(i); b.eb(i); } else{ r.eb(i); r.eb(b.back()); } } } else{ r.pop_back(); if(!r.size()){ if(ch==st){ reverse(all(b)); ch=b.back(); r.eb(ch); if(str[ch][i]=='R'){ b.pop_back(); r.eb(i); b.eb(i); } else{ r.pop_back(); r.eb(i); b.eb(i); } } else{ r.eb(i); b.eb(i); } } else{ if(str[i][r.back()]=='R'){ r.eb(i); b.eb(i); } else{ b.eb(i); b.eb(r.back()); } } } } printf("%d\n", n); if(r[0]!=st&&b[0]!=st)while(1); if(r.size()){ for(int i=0; i<r.size()-1; i++)assert(str[r[i]][r[i+1]]=='R'); } if(b.size()){ for(int i=0; i<b.size()-1; i++)assert(str[b[i]][b[i+1]]=='B'); } if(r[0]==st){ b.pop_back(); reverse(all(b)); for(auto i:r)printf("%d ", i); for(auto i:b)printf("%d ", i); } else{ r.pop_back(); reverse(all(r)); for(auto i:b)printf("%d ", i); for(auto i:r)printf("%d ", i); } puts(""); } int main(){ scanf("%d", &n); for(int i=2; i<=n; i++)scanf("%s", str[i]+1); if(n==2)return !printf("2\n1 2\n2\n2 1"); if(n==3)return !printf("3\n1 2 3\n3\n2 3 1\n3\n3 1 2"); for(int i=2; i<=n; i++){ for(int j=1; j<i; j++)str[j][i]=str[i][j]; } for(int i=1; i<=n; i++)solve(i); }
Compilation message
# | Verdict | Execution time | Memory | Grader output |
---|---|---|---|---|
1 | Correct | 0 ms | 384 KB | Output is correct |
2 | Correct | 1 ms | 384 KB | Output is correct |
3 | Correct | 0 ms | 384 KB | Output is correct |
4 | Correct | 0 ms | 256 KB | Output is correct |
5 | Correct | 0 ms | 384 KB | Output is correct |
6 | Correct | 1 ms | 384 KB | Output is correct |
7 | Correct | 0 ms | 256 KB | Output is correct |
8 | Correct | 0 ms | 256 KB | Output is correct |
9 | Correct | 0 ms | 384 KB | Output is correct |
10 | Correct | 0 ms | 384 KB | Output is correct |
11 | Correct | 1 ms | 384 KB | Output is correct |
12 | Runtime error | 2 ms | 512 KB | Execution killed with signal 11 |
13 | Halted | 0 ms | 0 KB | - |