Submission #274627

#	Time	Username	Problem	Language	Result	Execution time	Memory
274627		Falcon	Miners (IOI07_miners)	C++14	100 / 100	1301 ms	160888 KiB

miners

#pragma GCC optimize("O2")

#include <bits/stdc++.h>
#ifdef DEBUG
    #include "debug.hpp"
#endif

using namespace std;

#define all(c) (c).begin(), (c).end()
#define traverse(c, it) for(auto it = (c).begin(); it != (c).end(); it++)
#define rep(i, N) for(int i = 0; i < (N); i++)
#define rep1(i, N) for(int i = 1; i <= (N); i++)
#define rep2(i, s, e) for(int i = (s); i <= (e); i++)
#define rep3(i, s, e, d) for(int i = (s); (d) >= 0 ? i <= (e) : i >= (e); i += (d))
#define pb push_back


#ifdef DEBUG
    #define debug(x...) {dbg::depth++; string dbg_vals = dbg::to_string(x); dbg::depth--; dbg::fprint(__func__, __LINE__, #x, dbg_vals);}
    #define light_debug(x) {dbg::light = 1; dbg::dout << __func__ << ":" << __LINE__ << "  " << #x << " = " << x << endl; dbg::light = 0;}
#else
    #define debug(x...)
    #define light_debug(x) 
#endif

template<typename T>
T& ckmin(T& a, T b){ return a = a > b ? b : a; }

template<typename T>
T& ckmax(T& a, T b){ return a = a < b ? b : a; }

using ll = long long;
using pii = pair<int, int>;
using vi = vector<int>;

int N;
string s;

int dp[100000][4][4][4][4];
bool ch[100000][4][4][4][4];
map<char, int> c;

int rec(int i, int a, int b, int x, int y){
	if(i == N) return 0;
	if(ch[i][a][b][x][y]) return dp[i][a][b][x][y];
	set<int> tmp = {a, b, c[s[i]]};
	tmp.erase(0);
	int mine1 = tmp.size() + rec(i + 1, c[s[i]], a, x, y);
	tmp = {x, y, c[s[i]]};
	tmp.erase(0);
	int mine2 = tmp.size() + rec(i + 1, a, b, c[s[i]], x);
	ch[i][a][b][x][y] = 1;
	return dp[i][a][b][x][y] = max(mine1, mine2);
}

signed main(){

    ios_base::sync_with_stdio(false);
    cin.tie(0), cout.tie(0);

    #ifdef DEBUG
        freopen("debug", "w", stderr);
    #endif
	
	c['M'] = 1, c['F'] = 2, c['B'] = 3;
	cin >> N >> s;    

	cout << rec(0, 0, 0, 0, 0) << '\n';
    #ifdef DEBUG
        dbg::dout << "\nExecution time: " << clock() << "ms\n";
    #endif

    return 0;
}

• Subtask 1: 9 / 9
• Subtask 2: 9 / 9
• Subtask 3: 9 / 9
• Subtask 4: 9 / 9
• Subtask 5: 9 / 9
• Subtask 6: 7 / 7
• Subtask 7: 8 / 8
• Subtask 8: 8 / 8
• Subtask 9: 8 / 8
• Subtask 10: 8 / 8
• Subtask 11: 8 / 8
• Subtask 12: 8 / 8