# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
274130 | egekabas | Fishing Game (RMI19_fishing) | C++14 | 435 ms | 397872 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#define all(x) (x).begin(), (x).end()
#define ff first
#define ss second
#define pb push_back
#define mp make_pair
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef pair<ll, ll> pll;
typedef pair<ull, ull> pull;
typedef pair<int, int> pii;
typedef pair<ld, ld> pld;
ll mod = 1e9+7;
int n, t;
ll dp[209][209][209][3][2];
ll fact[209];
ll f(int a, int b, int ab, int cur, int done){
if(a < 0 || b < 0 || ab < 0)return 0;
if(cur == 0 && done == 1)
return dp[a][b][ab][cur][done] = f(a, b, ab, cur, 0);
if(dp[a][b][ab][cur][done] != -1)
return dp[a][b][ab][cur][done];
if(a == 0){
if(cur == 2 && done == 0)
return dp[a][b][ab][cur][done] = 0;
return dp[a][b][ab][cur][done] = fact[b];
}
dp[a][b][ab][cur][done] = 0;
int c = a-ab+b-ab;
dp[a][b][ab][cur][done] += ab*f(b-1, c, b-ab, (cur+1)%3, 1)%mod;
if(!(done == 0 && cur == 2))
dp[a][b][ab][cur][done] += (a-ab)*f(b+1, c, b-ab+1, (cur+1)%3, done)%mod;
dp[a][b][ab][cur][done] %= mod;
return dp[a][b][ab][cur][done];
}
vector<int> clean(vector<int> v){
sort(all(v));
vector<int> ret;
for(int i = 0; i < v.size(); ++i){
if(i == v.size()-1 || v[i] != v[i+1])
ret.pb(v[i]);
else
++i;
}
return ret;
}
void solve(){
vector<int> a(2*n), b(2*n), c(2*n);
for(int i = 0; i < 2*n; ++i)
cin >> a[i];
for(int i = 0; i < 2*n; ++i)
cin >> b[i];
for(int i = 0; i < 2*n; ++i)
cin >> c[i];
a = clean(a);
b = clean(b);
int abcon = 0;
for(int i = 0; i < a.size(); ++i)
for(int j = 0; j < b.size(); ++j)
if(a[i] == b[j])
abcon++;
cout << f(a.size(), b.size(), abcon, 0, 0) << '\n';
}
int main() {
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
//freopen("in.txt", "r", stdin);
//freopen("out.txt", "w", stdout);
cin >> n >> t;
for(int i = 0; i <= 200; ++i)
for(int j = 0; j <= 200; ++j)
for(int k = 0; k <= 200; ++k){
dp[i][j][k][0][0] = dp[i][j][k][1][0] = dp[i][j][k][2][0] = -1;
dp[i][j][k][0][1] = dp[i][j][k][1][1] = dp[i][j][k][2][1] = -1;
}
fact[0] = 1;
for(ll i = 1; i <= 200; ++i)
fact[i] = i*fact[i-1]%mod;
while(t--){
solve();
}
}
Compilation message (stderr)
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