Submission #266631

#	Time	Username	Problem	Language	Result	Execution time	Memory
266631		MarcoMeijer	Mousetrap (CEOI17_mousetrap)	C++14	0 / 100	169 ms	70520 KiB

mousetrap

#include <bits/stdc++.h>
using namespace std;

// macros
typedef long long ll;
typedef long double ld;
typedef pair<int, int> ii;
typedef pair<ll, ll> lll;
typedef tuple<int, int, int> iii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef vector<iii> viii;
typedef vector<ll> vll;
typedef vector<lll> vlll;
#define REP(a,b,c) for(int a=int(b); a<int(c); a++)
#define RE(a,c) REP(a,0,c)
#define RE1(a,c) REP(a,1,c+1)
#define REI(a,b,c) REP(a,b,c+1)
#define REV(a,b,c) for(int a=int(c-1); a>=int(b); a--)
#define FOR(a,b) for(auto& a : b)
#define all(a) a.begin(), a.end()
#define INF 1e9
#define EPS 1e-9
#define pb push_back
#define popb pop_back
#define fi first
#define se second
#define sz size()
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());

// input
template<class T> void IN(T& x) {cin >> x;}
template<class H, class... T> void IN(H& h, T&... t) {IN(h); IN(t...); }

// output
template<class T1, class T2> void OUT(const pair<T1,T2>& x);
template<class T> void OUT(const T& x) {cout << x;}
template<class H, class... T> void OUT(const H& h, const T&... t) {OUT(h); OUT(t...); }
template<class T1, class T2> void OUT(const pair<T1,T2>& x) {OUT(x.fi,' ',x.se);}
template<class... T> void OUTL(const T&... t) {OUT(t..., "\n"); }
template<class H> void OUTLS(const H& h) {OUTL(h); }
template<class H, class... T> void OUTLS(const H& h, const T&... t) {OUT(h,' '); OUTLS(t...); }

//===================//
//  Added libraries  //
//===================//

//===================//
//end added libraries//
//===================//

void program();
int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
    program();
}


//===================//
//   begin program   //
//===================//

const int MX = 5e5;

int n, t, m;
int a[MX], b[MX];
vi adj[MX];
vi path;

bool dfsPath(int u, int p=-1) {
    if(u == 1) {
        path.pb(u);
        return 1;
    }
    FOR(v,adj[u]) if(v != p) {
        if(dfsPath(v,u)) {
            path.pb(u);
            return 1;
        }
    }
    return 0;
}

void program() {
    IN(n,t,m);
    RE(i,n) IN(a[i], b[i]);
    RE(i,n) adj[a[i]].pb(b[i]);
    RE(i,n) adj[b[i]].pb(a[i]);
    dfsPath(m);
    reverse(all(path));

    int ans = 0;
    int prev = -1;
    RE(i,path.sz-1) {
        int u=path[i];
        int cnt1=0, cnt2=0;
        FOR(v,adj[u]) if(v != path[i+1] && v != prev) {
            if(adj[v].sz == 1) cnt1++;
            else cnt2++;
        }
        if(cnt2) cnt2--, cnt1++;
        ans += cnt1 + cnt2*2;
        prev = u;
    }
    OUTL(ans);
}

• Subtask 1: 0 / 20
• Subtask 2: 0 / 25
• Subtask 3: 0 / 20
• Subtask 4: 0 / 35