Submission #258004

#	Time	Username	Problem	Language	Result	Execution time	Memory
258004		leaked	Kisik (COCI19_kisik)	C++14	0 / 90	226 ms	19064 KiB

kisik

#include<bits/stdc++.h>
using namespace std;
//#include<ext/pb_ds/assoc_container.hpp>
//#include<ext/pb_ds/tree_policy.hpp>
//
//    #pragma GCC optimize("unroll-loops")
//    #pragma GCC optimize("Ofast")
//    #pragma GCC optimize("-O3")
//    #pragma GCC optimize("no-stack-protector")
//    #pragma GCC optimize("fast-math")
//#pragma GCC optimize("Ofast")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx")
//#define LOCAL
#define sim template < class c
#define ris return * this
#define dor > debug & operator <<
#define eni(x) sim > typename \
  enable_if<sizeof dud<c>(0) x 1, debug&>::type operator<<(c i) {
sim > struct rge { c b, e; };
sim > rge<c> range(c i, c j) { return rge<c>{i, j}; }
sim > auto dud(c* x) -> decltype(cerr << *x, 0);
sim > char dud(...);
struct debug {
#ifndef LOCAL
~debug() { cerr << endl; }
eni(!=) cerr << boolalpha << i; ris; }
eni(==) ris << range(begin(i), end(i)); }
sim, class b dor(pair < b, c > d) {
  ris << "(" << d.first << ", " << d.second << ")";
}
sim dor(rge<c> d) {
  *this << "[";
  for (auto it = d.b; it != d.e; ++it)
	*this << ", " + 2 * (it == d.b) << *it;
  ris << "]";
}
#else
sim dor(const c&) { ris; }
#endif
};
#define imie(...) " [" << #__VA_ARGS__ ": " << (__VA_ARGS__) << "] "
#define fi first
#define f first
#define se second
#define s second
#define vi_a vector<int>a;
#define p_b push_back
////////////////////////////////???????????????CHECK THIS OUT???????????????//////////////////////////////
#define ll long long
typedef unsigned long long ull;
////////////////////////////////???????????????CHECK THIS OUT???????????????//////////////////////////////
#define ld long double
#define pll pair<ll,ll>
#define pii pair<int,int>
#define m_p make_pair
#define fast_io cin.tie(0);cout.tie(0);ios_base::sync_with_stdio(0);
#define all(x) x.begin(),x.end()
#define getfiles    ifstream cin("input.txt");ofstream cout("output.txt");
#define pw(x) (1ll << x)
#define sz(x) (int)x.size()
#define endl "\n"
#define rall(x) x.rbegin(),x.rend()
#define len(a) (ll)a.size()
#define rep(x,l,r) for(ll x=l;x<r;x++)

//using namespace __gnu_pbds;
ld eps = (ld)1 / 1e6;
const ld pi=3.14159265359;
ll inf = 1e18,mod1=1e9+7;
ll sqr(ll a) { return a * a; }
ll qb(ll a) { return a * a * a; }
void umin(ll &a,ll b){a=min(a,b);}
void umax(int &a,int b){a=max(a,b);}
bool is_prime(ll val){for(ll i=2;i<=sqrt(val);i++)if(val%i==0)return 0; return 1;}
ll gcd(ll a, ll b) { return !a ? b : gcd(b % a, a); }
ll binpow(ll a, ll b, ll mod) { return b ? (b % 2 ? (a * (sqr(binpow(a, b / 2, mod)) % mod)) % mod : sqr(binpow(a, b / 2, mod)) % mod) : 1; }
ll binmult(ll a, ll b, ll mod) { return b ? (b % 2 ? (2 * binmult(a, b / 2, mod) + a) % mod : (2 * binmult(a, b / 2, mod)) % mod) : 0; }
/////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
const ll tx[4]={0,1,-1,1};
const ll ty[4]={-1,0,1,1};
const char rev_to[4]={'E','W','N','S'};
const int M=1e9;
const int N=2e5+2;
const int ppp=73;
const int lg=19;
const int OPEN=1;
const int CLOSE=0;
//typedef tree<ll,null_type,less<ll>,rb_tree_tag,tree_order_statistics_node_update> st;
auto rnd=bind(uniform_int_distribution<ll>(1,N),mt19937(time(0)));
void bad(){
    cout<<"NE";
    exit(0);
}
vector<int>g[N];
bool used[N];
bool col[N];
map<pii,int>mp;
void dfs(int v,int p){
    used[v]=1;
    if(p!=-1) col[v]=1;
    for(auto &z : g[v]){
        if(mp[{z,v}]) continue;
         mp[{z,v}]=1;
        dfs(z,v);
    }
}
int p[N],n,m;
signed main()
{
//    freopen("in.txt","r",stdin);
    fast_io;
    ///макс по высоте
    int n,k;
    cin>>n>>k;
    vector<pii>kek(n);
    for(auto &z : kek) cin>>z.s>>z.f,z.s*=-1;
    sort(rall(kek));/// окно длиной k
    for(auto &z : kek) z.s*=-1;
    ll w=0;
    ll ans=0;
    for(int i=0;i<k;i++){
        w+=kek[i].s;
        ans+=kek[i].f*kek[i].s;
    }
    ll mn=inf;
    for(int i=k;i<n;i++){
        umin(mn,kek[i-k].f*w);
//        debug()<<imie(kek);
//        ans-=1ll*kek[i-k].f*kek[i-k].s;
        w-=kek[i-k].s;
        w+=kek[i].s;
//        ans+=1ll*kek[i-0].f*kek[i-0].s;
    }
//    debug()<<imie(kek);
    umin(mn,kek[n-k].f*w);
    cout<<mn;
    return 0;
}
/*

*/

• Subtask 1: 0 / 10
• Subtask 2: 0 / 10
• Subtask 3: 0 / 10
• Subtask 4: 0 / 10
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