Submission #254147

#	Time	Username	Problem	Language	Result	Execution time	Memory
254147		khangal	Sky Walking (IOI19_walk)	C++14	10 / 100	629 ms	153080 KiB

walk

#include<bits/stdc++.h>
using namespace std;
typedef long long ll; 
typedef pair<ll,ll> pl;
typedef vector<ll> vl;
#define po pop_back
#define pb push_back
#define mk make_pair
#define lw lower_bound
#define up upper_bound
#define ff first
#define ss second
#define boost ios_base::sync_with_stdio(); cin.tie(0); cout.tie(0);
#define MOD 1000000007
#define MAX 1e18
#define MIN -1e18
#define rep(i,a,b) for(ll i=a;i<=b;i++)
#define per(i,a,b) for(ll i=b;i>=a;i--)
#define con continue
#define freopen freopen("input.txt", "r", stdin);freopen("output.txt", "w", stdout);
#define PI 3.14159265358979323846264338327950288419716939937510582097494459230781640628
// typedef tree<ll , null_type, less<ll>, rb_tree_tag, tree_order_statistics_node_update> indexed_set;
// template< typename T>
// using indexed_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
ll n,m,ans,mid,mn,mx,T,sum,h1,h2,e[1234567],b[1234567],c[1234567],d[1<<20],k,i,j,l,r,h,a[1234567],w,x,y,z;
bool used[1234567];
vector<int> v[1234567],vec,vv1,vv2;
string s1,s;
long long sz[1234567],par[1234567],tr[3234567],dist[123][123];
ll dx[4]={-1,1,0,0},dy[4]={0,0,-1,1},c1[123][123];
vector<array<ll, 3>> adj[123][123];
const long long inf  = 1e18 + 7;
const int kN = 63;
ll search(ll id, ll val){
    return lw(v[id].begin(), v[id].end(), val) - v[id].begin();
}
long long djikstra(int start1, int start2, int end1, int end2){
    for(int i = 0; i < kN; ++i)
        for(int j = 0; j < kN; ++j)
            dist[i][j] = inf;
    priority_queue<array<long long, 3>, vector<array<long long, 3>>, greater<array<long long, 3>>> pq;
    dist[start1][start2] = 0;
    pq.push({0, start1, start2});
    while(!pq.empty()){
        array<long long, 3> state = pq.top();
        pq.pop();
 
        int u1 = state[1], u2 = state[2];
        if(state[0] != dist[u1][u2])
            continue;
        if(u1 == end1 && u2 == end2)
            break;
 
        for(auto edge: adj[u1][u2]){
            int to1 = edge[0], to2 = edge[1];
            if(dist[to1][to2] > dist[u1][u2] + edge[2]){
                dist[to1][to2] = dist[u1][u2] + edge[2];
                pq.push({dist[to1][to2], to1, to2});
            }
        }
    }
 
    return dist[end1][end2];
}
long long min_distance(vector<int> x, vector<int> h, vector<int> l, vector<int> r, vector<int> y, int s, int g){
    n = x.size();
    m = y.size();
    sort(x.begin(),x.end());
    for(int i = 0; i < m; ++i){
        for(int j = l[i]; j <= r[i]; ++j){
            if(h[j] >= y[i])
                v[j].push_back(y[i]);
        }
    }
    for(int i = 0; i < n; ++i){
        v[i].push_back(0);
        v[i].push_back(h[i]);
    }
    for(int i = 0; i < n; ++i)
        sort(v[i].begin(), v[i].end());
    for(int i = 0; i < n; ++i){
        vector<int> vec;
        for(int j = 0; j < (int)v[i].size() - 1; ++j){
            if(v[i][j] != v[i][j + 1])
                vec.push_back(v[i][j]);
        }
        if(!v[i].empty())
            vec.push_back(v[i].back());
 
        v[i] = vec;
    }
    for(int i = 0; i < n; ++i){
        for(int j = 0; j < (int)v[i].size() - 1; ++j){
            adj[i][j].push_back({i, j + 1, v[i][j + 1] - v[i][j]});
            adj[i][j + 1].push_back({i, j, v[i][j + 1] - v[i][j]});
        }
    }
    for(int i = 0; i < m; ++i){
        int tmp = -1;
        for(int j = l[i]; j <= r[i]; ++j){
            if(h[j] >= y[i]){
                if(tmp == -1){
                    tmp = j;
                    continue;
                }
 
                int jj = search(j, y[i]), tmpp = search(tmp, y[i]);
                adj[j][jj].push_back({tmp, tmpp, x[j] - x[tmp]});
                adj[tmp][tmpp].push_back({j, jj, x[j] - x[tmp]});
 
                tmp = j;
            }
        }
    }
    ll res = djikstra(s,0,g,0);
    if(res==inf)return -1;
    else return res;
}

• Subtask 1: 10 / 10
• Subtask 2: 0 / 14
• Subtask 3: 0 / 15
• Subtask 4: 0 / 18
• Subtask 5: 0 / 43