Submission #254131

#	Time	Username	Problem	Language	Result	Execution time	Memory
254131		rama_pang	Coins (LMIO19_monetos)	C++14	100 / 100	86 ms	106148 KiB

monetos

#include <bits/stdc++.h>
using namespace std;

const int MAXN = 65;
const int INF = 1e8;

int T, N, K1, K2;
int A[305][305];
int ans[305][305];

int L[MAXN][MAXN];
int dp[MAXN][MAXN][MAXN * MAXN / 2];
pair<int, int> pr[MAXN][MAXN][MAXN * MAXN / 2];

void Solve() {
  int shift = max(1, N / 60);
  int NN = N / shift;
  for (int i = 1; i <= N; i++) {
    for (int j = 1; j <= N; j++) {
      int di = (i + shift - 1) / shift;
      int dj = (j + shift - 1) / shift;
      L[di][dj] += A[i][j];
    }
  }
  for (int i = 1; i <= NN; i++) {
    for (int j = 1; j <= NN; j++) {
      L[i][j] += L[i][j - 1];
    }
  }
  for (int i = 0; i < MAXN; i++) {
    for (int j = 0; j < MAXN; j++) {
      for (int k = 0; k < MAXN * MAXN / 2; k++) {
        dp[i][j][k] = INF;
        pr[i][j][k] = {-1, -1};
      }
    }
  }
  dp[NN + 1][0][0] = 0;
  for (int i = NN + 1; i >= 1; i--) {
    for (int j = 0; j <= NN; j++) {
      for (int k = 0; k <= NN * NN / 2; k++) if (dp[i][j][k] != INF) {
        if (k + j <= NN * NN / 2) {
          if (dp[i - 1][j][k + j] > dp[i][j][k] + L[i - 1][j]) {
            dp[i - 1][j][k + j] = dp[i][j][k] + L[i - 1][j];
            pr[i - 1][j][k + j] = {1, k};
          }
        }
        if (k <= NN * NN / 2) {
          if (dp[i][j + 1][k] > dp[i][j][k]) {
            dp[i][j + 1][k] = dp[i][j][k];
            pr[i][j + 1][k] = {0, k};
          }
        }
      }
    }
  }
  vector<vector<int>> res(NN + 2, vector<int>(NN + 2));
  int i = 1, j = NN, k = NN * NN / 2;
  while (i != NN + 1) {
    int ni, nj, nk;
    if (pr[i][j][k].first == 1) {
      for (int l = 1; l <= NN; l++) {
        res[i][l] = (l > j);
      }
      ni = i + 1, nj = j, nk = pr[i][j][k].second;
    } else {
      ni = i, nj = j - 1, nk = pr[i][j][k].second;
    }
    i = ni, j = nj, k = nk;
  }
  for (int i = 1; i <= NN; i++) {
    for (int j = 1; j <= NN; j++) {
      for (int k = 1; k <= shift; k++) {
        for (int l = 1; l <= shift; l++) {
          ans[(i - 1) * shift + k][(j - 1) * shift + l] = res[i][j];
        }
      }
    }
  }
}

int main() {
  ios::sync_with_stdio(0);
  cin.tie(0), cout.tie(0);

  cin >> T >> N >> K1 >> K2;
  for (int i = 1; i <= N; i++) {
    for (int j = 1; j <= N; j++) {
      cin >> A[i][j];
    }
  }
  Solve();
  for (int i = 1; i <= N; i++) {
    for (int j = 1; j <= N; j++) {
      cout << ans[i][j] << " \n"[j == N];
    }
  }
  return 0;
}

• Subtask 1: 100 / 100