Submission #254103

#	Time	Username	Problem	Language	Result	Execution time	Memory
254103		leaked	Sažetak (COCI17_sazetak)	C++14	0 / 160	1 ms	512 KiB

sazetak

#include<bits/stdc++.h>
using namespace std;
//#include<ext/pb_ds/assoc_container.hpp>
//#include<ext/pb_ds/tree_policy.hpp>
//
//    #pragma GCC optimize("unroll-loops")
//    #pragma GCC optimize("Ofast")
//    #pragma GCC optimize("-O3")
//    #pragma GCC optimize("no-stack-protector")
    #pragma GCC optimize("fast-math")
#pragma GCC optimize("Ofast")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx")
//#define LOCAL
#define sim template < class c
#define ris return * this
#define dor > debug & operator <<
#define eni(x) sim > typename \
  enable_if<sizeof dud<c>(0) x 1, debug&>::type operator<<(c i) {
sim > struct rge { c b, e; };
sim > rge<c> range(c i, c j) { return rge<c>{i, j}; }
sim > auto dud(c* x) -> decltype(cerr << *x, 0);
sim > char dud(...);
struct debug {
#ifndef LOCAL
~debug() { cerr << endl; }
eni(!=) cerr << boolalpha << i; ris; }
eni(==) ris << range(begin(i), end(i)); }
sim, class b dor(pair < b, c > d) {
  ris << "(" << d.first << ", " << d.second << ")";
}
sim dor(rge<c> d) {
  *this << "[";
  for (auto it = d.b; it != d.e; ++it)
	*this << ", " + 2 * (it == d.b) << *it;
  ris << "]";
}
#else
sim dor(const c&) { ris; }
#endif
};
#define imie(...) " [" << #__VA_ARGS__ ": " << (__VA_ARGS__) << "] "
#define fi first
#define f first
#define se second
#define s second
#define vi_a vector<int>a;
#define p_b push_back
////////////////////////////////???????????????CHECK THIS OUT???????????????//////////////////////////////
#define ll long long
typedef unsigned long long ull;
////////////////////////////////???????????????CHECK THIS OUT???????????????//////////////////////////////
#define ld long double
#define pll pair<ll,ll>
#define pii pair<int,int>
#define m_p make_pair
#define fast_io cin.tie(0);cout.tie(0);ios_base::sync_with_stdio(0);
#define all(x) x.begin(),x.end()
#define getfiles    ifstream cin("input.txt");ofstream cout("output.txt");
#define pw(x) (1ll << x)
#define sz(x) (int)x.size()
#define endl "\n"
#define rall(x) x.rbegin(),x.rend()
#define len(a) (ll)a.size()
#define rep(x,l,r) for(ll x=l;x<r;x++)

//using namespace __gnu_pbds;
ld eps = (ld)1 / 1e6;
const ld pi=3.14159265359;
ll inf = 1e18,mod1=1e9+7;
ll sqr(ll a) { return a * a; }
ll qb(ll a) { return a * a * a; }
ll gcd(ll a, ll b) { return !a ? b : gcd(b % a, a); }
ll binpow(ll a, ll b, ll mod) { return b ? (b % 2 ? (a * (sqr(binpow(a, b / 2, mod)) % mod)) % mod : sqr(binpow(a, b / 2, mod)) % mod) : 1; }
ll binmult(ll a, ll b, ll mod) { return b ? (b % 2 ? (2 * binmult(a, b / 2, mod) + a) % mod : (2 * binmult(a, b / 2, mod)) % mod) : 0; }
/////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
const ll R=1e4;
const ll tx[4]={0,0,-1,1};
const ll ty[4]={-1,1,0,0};
const char rev_to[4]={'E','W','N','S'};
const int N=5e2+1;
const int M=1e9+7;
const int Y=1;
const int X=0;
//typedef tree<ll,null_type,less<ll>,rb_tree_tag,tree_order_statistics_node_update> st;
auto rnd=bind(uniform_int_distribution<ll>(1,125),mt19937(time(0)));
void bad(){
    cout<<-1;
    exit(0);
}
bool mrk[N];
int s,t;
int c[N][N],f[N][N],n,m;
vector<int>g[N];
vector<int>p(N);
#define re return
int bfs(){
    p[s]=-2;
    queue<pii>q;
    q.push({s,2e9});
    while(!q.empty()){
        int v=q.front().f,flow=q.front().s;
        q.pop();
        for(auto &u : g[v]){
            if(p[u]==-1 && f[v][u]<c[v][u]){
                p[u]=v;
                if(u==t) return min(flow,c[v][u]-f[v][u]);
                q.push({u,min(flow,c[v][u]-f[v][u])});

            }
        }
    }
    return 0;
}
ll ans=0;
void find_flow(){
    while(1){
        fill(all(p),-1);
        int ps=bfs();
        if(!ps) break;
        int cur=t;
        while(cur!=s){
            int prev=p[cur];
            f[prev][cur]+=ps;
            f[cur][prev]-=ps;
            cur=prev;
        }
        ans+=ps;
    }
}
signed main()
{
    fast_io;
    cin>>n>>m;
    s=0,t=n-1;
    int v,u,cc;
    while(m--){
        cin>>v>>u>>cc;--v;--u;
        c[v][u]=cc;
        g[v].p_b(u);
        g[u].p_b(v);
    }
    find_flow();
    cout<<ans;
    return 0;
}
/*
0 0 0
2 1 3
3 2 7
1 3 8
1 4 2
3 5 3

/
*/

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