Submission #25328

#	Time	Username	Problem	Language	Result	Execution time	Memory
25328		dotorya	Secret (JOI14_secret)	C++14	0 / 100	609 ms	6640 KiB

secret

#include <stdio.h>  
#include <algorithm>  
#include <assert.h>
#include <bitset>
#include <cmath>  
#include <complex>  
#include <deque>  
#include <functional>  
#include <iostream>  
#include <limits.h>  
#include <map>  
#include <math.h>  
#include <queue>  
#include <set>  
#include <stdlib.h>  
#include <string.h>  
#include <string>  
#include <time.h>  
#include <unordered_map>  
#include <unordered_set>  
#include <vector>  

#pragma warning(disable:4996)  
#pragma comment(linker, "/STACK:336777216")  
using namespace std;

#define mp make_pair  
#define Fi first  
#define Se second  
#define pb(x) push_back(x)  
#define szz(x) ((int)(x).size())  
#define rep(i, n) for(int i=0;i<n;i++)  
#define all(x) (x).begin(), (x).end()  
#define ldb ldouble  

typedef tuple<int, int, int> t3;
typedef long long ll;
typedef unsigned long long ull;
typedef double db;
typedef long double ldb;
typedef pair <int, int> pii;
typedef pair <ll, ll> pll;
typedef pair <ll, int> pli;
typedef pair <db, db> pdd;

int IT_MAX = 1 << 18;
const ll MOD = 1000000007;
const int INF = 0x3f3f3f3f;
const ll LL_INF = 0x3f3f3f3f3f3f3f3f;
const db PI = acos(-1);
const db ERR = 1e-10;

#include "secret.h"

map <int, int> Mx1[1050];
map <int, int> Mx2[1050];
int mySecret(int a, int b) {
	if (a == -1) return b;
	if (b == -1) return a;
	return Secret(a, b);
}
void Init(int N, int A[]) {
	int i, j;
	for (i = N; i >= 1; i--) {
		int prv = -1;
		for (j = i; j <= N; j += j & (-j)) {
			if (i == j) Mx1[i][i] = A[i-1];
			else Mx1[i][j] = mySecret(Mx1[i][prv], Mx1[prv + 1][j]);
			prv = j;
		}
	}
	for (i = 1; i <= N; i++) {
		int prv = -1;
		for (j = i; j; j -= j & (-j)) {
			if (i == j) Mx2[i][j] = -1;
			else if (j + 1 == i) Mx2[i][j] = A[i-1];
			else Mx2[i][j] = mySecret(Mx2[i][prv], Mx2[prv][j]);
			prv = j;
		}
	}
}

int Query(int L, int R) {
	L++, R++;
	
	set <int> Su1;
	set <int> Su2;
	for (int t = L; t <= R; t += t & (-t)) Su1.insert(t);
	for (int t = R; t >= L; t -= t & (-t)) {
		if (Su1.count(t)) return mySecret(Mx1[L][t], Mx2[R][t]);
	}
	return 0;
}

Compilation message (stderr)

secret.cpp:23:0: warning: ignoring #pragma warning  [-Wunknown-pragmas]
 #pragma warning(disable:4996)  
 ^
secret.cpp:24:0: warning: ignoring #pragma comment  [-Wunknown-pragmas]
 #pragma comment(linker, "/STACK:336777216")  
 ^

• Subtask 1: 0 / 100