This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
struct SegTree {
int n;
vector<int> st;
void init(int _n) {
n = _n;
st.assign(4*n, 0);
}
void upd(int p, int i, int j, int k, int v) {
if (k < i || k > j) return;
if (i == j) {
st[p] = v;
} else {
upd(p << 1, i, (i+j)/2, k, v);
upd((p << 1) + 1, (i+j)/2+1, j, k, v);
st[p] = max(st[p*2],st[p*2+1]);
}
}
void upd(int p, int v) {
upd(1, 0, n-1, p, v);
}
int qry(int p, int i, int j, int L, int R) {
if (R < i || L > j) return 0;
if (L <= i && j <= R) return st[p];
return max(qry(p << 1, i, (i+j)/2, L, R), qry((2*p+1), (i+j)/2+1, j, L, R));
}
int qry(int i, int j) {
return qry(1, 0, n-1, i, j);
}
int qry2(int p, int i, int j, int mx) {
if (i == j) {
if (st[p] > mx) return i;
return -1;
}
if (st[p] <= mx) return -1;
if (st[p*2] > mx) return qry2(p << 1, i, (i+j)/2, mx);
return qry2(p*2+1, (i+j)/2+1, j, mx);
}
int qry2(int mx) {
int res = qry2(1, 0, n-1, mx);
assert(res != -1);
return res;
}
} lft, rht;
int main() {
cin.tie(0); ios_base::sync_with_stdio(0);
int n, a; cin >> n >> a; --a;
int A[n];
int loc[11]; for (int i = 1; i <= 10; i++) loc[i] = -1;
lft.init(a+1); rht.init(n-a);
for (int i = 0; i < n; i++) {
cin >> A[i];
if (A[i] >= n-9) {
loc[n+1-A[i]] = i;
}
if (i < a) {
lft.upd(a-1-i, A[i]);
} else if (i > a) {
rht.upd(i-a-1, A[i]);
}
}
lft.upd(a, 1e9);
rht.upd(n-a-1, 1e9);
int idx = n+1;
int q; cin >> q;
for (int qi = 0; qi < q; qi++) {
char c; cin >> c;
if (c == 'E') {
int i, e; cin >> i >> e; --i;
for (int x = 10; x >= 1; x--) {
if (loc[x] == i) {
for (int y = x; y <= 9; y++) {
loc[y] = loc[y+1];
}
break;
}
}
for (int x = 9; x >= e; x--) {
loc[x+1] = loc[x];
}
loc[e] = i;
for (int x = 10; x >= 1; x--) {
int l = loc[x];
if (l == -1) continue;
if (l < a) lft.upd(a-1-l, idx++);
else if (l > a) rht.upd(l-a-1, idx++);
A[l] = idx-1;
}
} else {
int b; cin >> b; --b;
if (b == a) cout << 0 << "\n";
else {
if (b < a) {
int mx = lft.qry(0,a-1-b);
int idx = rht.qry2(mx);
cout << a-b+idx << "\n";
} else {
int mx = rht.qry(0,b-a-1);
int idx = lft.qry2(mx);
cout << b-a+idx << "\n";
}
}
}
}
return 0;
}
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