#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<int> vi;
typedef vector<vector<int> > vvi;
typedef vector<ll> vll;
#define forn(i, n) for (int (i) = 0; (i) != (n); (i)++)
#define all(v) (v).begin(), (v).end()
#define rall(v) (v).rbegin(), (v).rend()
#define popcount(x) __builtin_popcount(x)
#define popcountll(x) __builtin_popcountll(x)
#define fi first
#define se second
#define re return
#define pb push_back
#define uniq(x) sort(all(x)); (x).resize(unique(all(x)) - (x).begin())
#ifdef LOCAL
#define dbg(x) cerr << __LINE__ << " " << #x << " " << x << endl
#define ln cerr << __LINE__ << endl
#else
#define dbg(x) void(0)
#define ln void(0)
#endif // LOCAL
const int N = 2005;
int check(int n, int a, int b, vector<ll> &p, ll mask)
{
vector<bitset<N> > dp(n + 1, bitset<N>());
dp[0][0] = 1;
for (int i = 1; i <= n; i++)
{
for (int j = 0; j < i; j++)
{
ll x = p[i] - p[j];
if ((x & mask) == x)
{
dp[i] |= dp[j] << 1;
}
}
}
for (int i = a; i <= b; i++) if (dp[n][i]) return 1;
return 0;
}
signed main()
{
int n, a, b;
cin >> n >> a >> b;
vector<ll> x(n);
forn(i, n) cin >> x[i];
vector<ll> p(n + 1);
for (int i = 1; i <= n; i++) p[i] = x[i - 1] + p[i - 1];
ll ans = (1ll << 60) - 1;
for (int j = 59; j >= 0; j--)
{
if (check(n, a, b, p, ans - (1ll << j)))
{
ans -= (1ll << j);
}
}
cout << ans;
}
/* Note:
Check constants at the beginning of the code.
N is set to 4e5 but be careful in problems with large constant factor.
Setting N in every problem is more effective.
Check corner cases.
N = 1
No def int long long for now.
Add something here.
*/
