Submission #251754

#	Time	Username	Problem	Language	Result	Execution time	Memory
251754		jamielim	Exhibition (JOI19_ho_t2)	C++14	100 / 100	85 ms	4472 KiB

joi2019_ho_t2

//#include "lost.h"
#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef pair<int,int> ii;
typedef pair<ll,ll> pll;
typedef long double ld;
#define mp make_pair
#define pb push_back
#define fi first
#define se second
#define ALL(x) x.begin(),x.end()
#define SZ(x) (int)x.size()
const int INF=2012345678;
const ll LLINF=4012345678012345678LL;
const ll MOD=1000000007; //998244353; //
const ld PI=3.1415926535898;
const ld EPS=1e-9;
ll gcd(ll a,ll b){if(a<b)swap(a,b);if(b==0)return a;return gcd(b,a%b);}
inline ll lcm(ll a,ll b){return a/gcd(a,b)*b;}
inline ll expo(ll b,ll p,ll m){ll res=1; while(p){if(p&1)res=(res*b)%m; b=(b*b)%m; p>>=1;} return res;}
inline ll modinv(ll a,ll m){return expo(a,m-2,m);}

int main(){
	int n,m;
	scanf("%d%d",&n,&m);
	ii p[n];
	for(int i=0;i<n;i++)scanf("%d%d",&p[i].se,&p[i].fi);
	int c[m];
	for(int i=0;i<m;i++)scanf("%d",&c[i]);
	sort(p,p+n);sort(c,c+m);
	int l=0,r=min(n,m);
	while(l<r){
		int mid=(l+r+1)/2;
		int idx=0;
		bool poss=1;
		for(int i=m-mid;i<m;i++){
			while(idx<n&&p[idx].se>c[i])idx++;
			if(idx==n){poss=0;break;}
			idx++;
		}
		if(poss)l=mid;
		else r=mid-1;
	}
	printf("%d",l);
}

Compilation message (stderr)

joi2019_ho_t2.cpp: In function 'int main()':
joi2019_ho_t2.cpp:27:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf("%d%d",&n,&m);
  ~~~~~^~~~~~~~~~~~~~
joi2019_ho_t2.cpp:29:27: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  for(int i=0;i<n;i++)scanf("%d%d",&p[i].se,&p[i].fi);
                      ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~
joi2019_ho_t2.cpp:31:27: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  for(int i=0;i<m;i++)scanf("%d",&c[i]);
                      ~~~~~^~~~~~~~~~~~

• Subtask 1: 10 / 10
• Subtask 2: 40 / 40
• Subtask 3: 50 / 50