Submission #249563

#	Time	Username	Problem	Language	Result	Execution time	Memory
249563		VEGAnn	Klavir (COCI17_klavir)	C++14	0 / 160	185 ms	45432 KiB

klavir

#include <bits/stdc++.h>
//#pragma GCC optimize("unroll-loops")
//#pragma GCC optimize("-O3")
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize("no-stack-protector")
//#pragma GCC optimize("fast-math")
#define all(x) x.begin(),x.end()
#define sz(x) ((int)x.size())
using namespace std;
typedef long long ll;
const int M = 1000100;
const int N = 110;
const int md = int(1e9) + 7;
bitset<N> was[M];
int a[M], n, m, ans[M], pf[M], bb[M], summ[M];

int mult(int x, int y) { return (1ll * x * y) % md; }

int sum(int x, int y){
    x += y;
    if (x >= md)
        x -= md;
    return x;
}

int sub(int x, int y){
    x -= y;
    if (x < 0)
        x += md;
    return x;
}

int main(){
    ios_base::sync_with_stdio(0); cin.tie(0);

#ifdef _LOCAL
    freopen("in.txt","r",stdin);
#endif // _LOCAL

    cin >> n >> m;

    for (int i = 1; i <= m; i++) {
        cin >> a[i];
        bb[i - 1] = a[i];
    }

    ans[0] = 0;

    pf[0] = 0;

    for (int i = 1; i < m; i++){
        int j = pf[i - 1];

        while (j > 0 && bb[i] != bb[j])
            j = pf[j - 1];

        if (bb[i] == bb[j])
            j++;

        pf[i] = j;
    }

    summ[0] = 0;

    for (int i = 1; i <= m; i++){
        ans[i] = mult(sum(ans[i - 1], 1), n);

        int id = i - 1;

        summ[id] = summ[pf[i - 1]];

        ans[i] = sub(ans[i], summ[id]);

        was[i] = was[pf[i]];

        if (was[i][a[i]]){
            summ[id] = sum(summ[id], ans[i]);

            int pos = i - 1;

            while (a[pos + 1] != a[i]){
                pos = pf[pos];
            }

            summ[id] = sub(summ[id], ans[pos + 1]);
        } else {
            was[i][a[i]] = 1;
            summ[id] = sum(summ[id], ans[i]);
        }

//        for (int j = 1; j <= n; j++)
//            if (a[i] != j){
//                int mx = aut[i][j];
//                ans[i] = sub(ans[i], ans[mx]);
//            }

        cout << ans[i] << '\n';
    }

    return 0;
}

• Subtask 1: 0 / 16
• Subtask 2: 0 / 16
• Subtask 3: 0 / 16
• Subtask 4: 0 / 16
• Subtask 5: 0 / 16
• Subtask 6: 0 / 16
• Subtask 7: 0 / 16
• Subtask 8: 0 / 16
• Subtask 9: 0 / 16
• Subtask 10: 0 / 16