Submission #248613

#	Time	Username	Problem	Language	Result	Execution time	Memory
248613		rqi	Birthday gift (IZhO18_treearray)	C++14	100 / 100	891 ms	101084 KiB

treearray

#include <bits/stdc++.h>
using namespace std;
 
typedef long long ll;
typedef long double ld;
typedef double db; 
typedef string str; 

typedef pair<int,int> pi;
typedef pair<ll,ll> pl; 
typedef pair<db,db> pd; 

typedef vector<int> vi; 
typedef vector<ll> vl; 
typedef vector<db> vd; 
typedef vector<str> vs; 
typedef vector<pi> vpi;
typedef vector<pl> vpl; 
typedef vector<pd> vpd; 

#define mp make_pair
#define f first
#define s second
#define sz(x) (int)x.size()
#define all(x) begin(x), end(x)
#define rall(x) (x).rbegin(), (x).rend() 
#define rsz resize
#define ins insert 
#define ft front() 
#define bk back()
#define pf push_front 
#define pb push_back
#define eb emplace_back 
#define lb lower_bound 
#define ub upper_bound 

#define FOR(i,a,b) for (int i = (a); i < (b); ++i)
#define F0R(i,a) FOR(i,0,a)
#define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i)
#define R0F(i,a) ROF(i,0,a)
#define trav(a,x) for (auto& a: x)

const int MOD = 1e9+7; // 998244353;
const int MX = 2e5+5; 
const ll INF = 1e18; 
const ld PI = acos((ld)-1);
const int xd[4] = {1,0,-1,0}, yd[4] = {0,1,0,-1}; 
mt19937 rng((uint32_t)chrono::steady_clock::now().time_since_epoch().count()); 

template<class T> bool ckmin(T& a, const T& b) { 
    return b < a ? a = b, 1 : 0; }
template<class T> bool ckmax(T& a, const T& b) { 
    return a < b ? a = b, 1 : 0; } 
int pct(int x) { return __builtin_popcount(x); } 
int bits(int x) { return 31-__builtin_clz(x); } // floor(log2(x)) 
int cdiv(int a, int b) { return a/b+!(a<0||a%b == 0); } // division of a by b rounded up, assumes b > 0 
int fstTrue(function<bool(int)> f, int lo, int hi) {
    hi ++; assert(lo <= hi); // assuming f is increasing
    while (lo < hi) { // find first index such that f is true 
        int mid = (lo+hi)/2; 
        f(mid) ? hi = mid : lo = mid+1; 
    } 
    return lo;
}

// INPUT
template<class A> void re(complex<A>& c);
template<class A, class B> void re(pair<A,B>& p);
template<class A> void re(vector<A>& v);
template<class A, size_t SZ> void re(array<A,SZ>& a);

template<class T> void re(T& x) { cin >> x; }
void re(db& d) { str t; re(t); d = stod(t); }
void re(ld& d) { str t; re(t); d = stold(t); }
template<class H, class... T> void re(H& h, T&... t) { re(h); re(t...); }

template<class A> void re(complex<A>& c) { A a,b; re(a,b); c = {a,b}; }
template<class A, class B> void re(pair<A,B>& p) { re(p.f,p.s); }
template<class A> void re(vector<A>& x) { trav(a,x) re(a); }
template<class A, size_t SZ> void re(array<A,SZ>& x) { trav(a,x) re(a); }

// TO_STRING
#define ts to_string
str ts(char c) { return str(1,c); }
str ts(bool b) { return b ? "true" : "false"; }
str ts(const char* s) { return (str)s; }
str ts(str s) { return s; }
template<class A> str ts(complex<A> c) { 
    stringstream ss; ss << c; return ss.str(); }
str ts(vector<bool> v) { 
    str res = "{"; F0R(i,sz(v)) res += char('0'+v[i]);
    res += "}"; return res; }
template<size_t SZ> str ts(bitset<SZ> b) {
    str res = ""; F0R(i,SZ) res += char('0'+b[i]);
    return res; }
template<class A, class B> str ts(pair<A,B> p);
template<class T> str ts(T v) { // containers with begin(), end()
    bool fst = 1; str res = "{";
    for (const auto& x: v) {
        if (!fst) res += ", ";
        fst = 0; res += ts(x);
    }
    res += "}"; return res;
}
template<class A, class B> str ts(pair<A,B> p) {
    return "("+ts(p.f)+", "+ts(p.s)+")"; }

// OUTPUT
template<class A> void pr(A x) { cout << ts(x); }
template<class H, class... T> void pr(const H& h, const T&... t) { 
    pr(h); pr(t...); }
void ps() { pr("\n"); } // print w/ spaces
template<class H, class... T> void ps(const H& h, const T&... t) { 
    pr(h); if (sizeof...(t)) pr(" "); ps(t...); }

// DEBUG
void DBG() { cerr << "]" << endl; }
template<class H, class... T> void DBG(H h, T... t) {
    cerr << ts(h); if (sizeof...(t)) cerr << ", ";
    DBG(t...); }
#ifdef LOCAL // compile with -DLOCAL
#define dbg(...) cerr << "LINE(" << __LINE__ << ") -> [" << #__VA_ARGS__ << "]: [", DBG(__VA_ARGS__)
#else
#define dbg(...) 0
#endif

// FILE I/O
void setIn(string s) { freopen(s.c_str(),"r",stdin); }
void setOut(string s) { freopen(s.c_str(),"w",stdout); }
void unsyncIO() { ios_base::sync_with_stdio(0); cin.tie(0); }
void setIO(string s = "") {
    unsyncIO();
    // cin.exceptions(cin.failbit); 
    // throws exception when do smth illegal
    // ex. try to read letter into int
    if (sz(s)) { setIn(s+".in"), setOut(s+".out"); } // for USACO
}


/**
 * Description: 1D range minimum query. Can also do queries 
     * for any associative operation in $O(1)$ with D\&C
 * Source: KACTL
 * Verification: 
    * https://cses.fi/problemset/stats/1647/
    * http://wcipeg.com/problem/ioi1223
    * https://pastebin.com/ChpniVZL
 * Memory: O(N\log N)
 * Time: O(1)
 */

template<class T> struct RMQ { // floor(log_2(x))
    int level(int x) { return 31-__builtin_clz(x); } 
    vector<T> v; vector<vi> jmp;
    int comb(int a, int b) { // index of min
        return v[a]==v[b]?min(a,b):(v[a]<v[b]?a:b); } 
    void init(const vector<T>& _v) {
        v = _v; jmp = {vi(sz(v))}; iota(all(jmp[0]),0);
        for (int j = 1; 1<<j <= sz(v); ++j) {
            jmp.pb(vi(sz(v)-(1<<j)+1));
            F0R(i,sz(jmp[j])) jmp[j][i] = comb(jmp[j-1][i],
                                    jmp[j-1][i+(1<<(j-1))]);
        }
    }
    int index(int l, int r) { // get index of min element
        int d = level(r-l+1);
        return comb(jmp[d][l],jmp[d][r-(1<<d)+1]); }
    T query(int l, int r) { return v[index(l,r)]; }
};


/**
 * Description: Euler Tour LCA. Compress takes a subset $S$ of nodes 
     * and computes the minimal subtree that contains all the nodes 
    * pairwise LCA's and compressing edges. Returns a list of
    * \texttt{(par, orig\_index)} representing a tree rooted at 0. 
    * The root points to itself.
 * Time: O(N\log N) build, O(1) LCA
 * Source: USACO, Simon Lindholm (KACTL)
 * Verification: USACO Debug the Bugs
     * https://codeforces.com/contest/1320/problem/E
 */

template<int SZ> struct LCA {
    int N, R = 1, depth[SZ], st[SZ];
    vi adj[SZ]; vpi tmp; RMQ<pi> r;
    void ae(int u, int v) { adj[u].pb(v), adj[v].pb(u); }
    void dfs(int u, int p) {
        st[u] = sz(tmp), depth[u] = depth[p]+1;
        tmp.eb(depth[u],u); 
        trav(v,adj[u]) if (v != p) 
            dfs(v,u), tmp.eb(depth[u],u);
    }
    void init(int _N) { N = _N; dfs(R,0); r.init(tmp); }
    int lca(int u, int v){
        u = st[u], v = st[v]; if (u > v) swap(u,v);
        return r.query(u,v).s; }
    /// int dist(int u, int v) {
        /// return depth[u]+depth[v]-2*depth[lca(u,v)]; }
    vpi compress(vi S) {
        static vi rev; rev.rsz(N+1);
        auto cmp = [&](int a, int b) { return st[a] < st[b]; };
        sort(all(S),cmp); R0F(i,sz(S)-1) S.pb(lca(S[i],S[i+1]));
        sort(all(S),cmp); S.erase(unique(all(S)),end(S));
        vpi ret{{0,S[0]}}; F0R(i,sz(S)) rev[S[i]] = i;
        F0R(i,sz(S)-1) ret.eb(rev[lca(S[i],S[i+1])],S[i+1]);
        return ret;
    }
};

const int mx = 200005;
LCA<mx> tre;
int a[mx];
set<int> sing[mx];
set<int> inds[mx];

int main() {
    setIO();
    int n, m, q;
    cin >> n >> m >> q;
    for(int i = 0; i < n-1; i++){
        int u, v;
        cin >> u >> v;
        tre.ae(u, v);
    }
    tre.init(n);
    for(int i = 1; i <= m; i++){
        cin >> a[i];
    }
    for(int i = 1; i <= m; i++){
        sing[a[i]].ins(i);
        if(i+1 <= m){
            inds[tre.lca(a[i], a[i+1])].ins(i);
        }
    }

    for(int i = 1; i <= q; i++){
        int typ;
        cin >> typ;
        if(typ == 1){
            int pos, v;
            cin >> pos >> v;
            sing[a[pos]].erase(pos);
            if(pos-1 >= 1){
                inds[tre.lca(a[pos-1], a[pos])].erase(pos-1);
            }
            if(pos+1 <= m){
                inds[tre.lca(a[pos], a[pos+1])].erase(pos);
            }

            a[pos] = v;

            sing[a[pos]].ins(pos);
            if(pos-1 >= 1){
                inds[tre.lca(a[pos-1], a[pos])].ins(pos-1);
            }
            if(pos+1 <= m){
                inds[tre.lca(a[pos], a[pos+1])].ins(pos);
            }
        }
        else{
            int l, r, v;
            cin >> l >> r >> v;
            auto it = sing[v].lb(l);
            if(it != sing[v].end() && *it <= r){
                ps(*it, *it);
                continue;
            }
            it = inds[v].lb(l);
            if(it != inds[v].end() && *it+1 <= r){
                ps(*it, *it+1);
                continue;
            }
            ps(-1, -1);
            continue;
        }
    }

    // you should actually read the stuff at the bottom
}

/* stuff you should look for
    * int overflow, array bounds
    * special cases (n=1?)
    * do smth instead of nothing and stay organized
    * WRITE STUFF DOWN
*/

Compilation message (stderr)

treearray.cpp: In function 'void setIn(std::__cxx11::string)':
treearray.cpp:128:31: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)', declared with attribute warn_unused_result [-Wunused-result]
 void setIn(string s) { freopen(s.c_str(),"r",stdin); }
                        ~~~~~~~^~~~~~~~~~~~~~~~~~~~~
treearray.cpp: In function 'void setOut(std::__cxx11::string)':
treearray.cpp:129:32: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)', declared with attribute warn_unused_result [-Wunused-result]
 void setOut(string s) { freopen(s.c_str(),"w",stdout); }
                         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~

• Subtask 1: 12 / 12
• Subtask 2: 18 / 18
• Subtask 3: 26 / 26
• Subtask 4: 44 / 44