Submission #247293

#	Time	Username	Problem	Language	Result	Execution time	Memory
247293		jamielim	Wine Tasting (FXCUP4_wine)	C++17	0 / 100	10 ms	732 KiB

bartender

#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef pair<int,int> ii;
typedef pair<ll,ll> pll;
typedef long double ld;
#define mp make_pair
#define pb push_back
#define fi first
#define se second
#define ALL(x) x.begin(),x.end()
#define SZ(x) (int)x.size()
const int INF=2012345678;
const ll LLINF=4012345678012345678LL;
const ll MOD=1000000007; //998244353; //
const ld PI=3.1415926535898;
const ld EPS=1e-9;
ll gcd(ll a,ll b){if(a<b)swap(a,b);if(b==0)return a;return gcd(b,a%b);}
inline ll lcm(ll a,ll b){return a/gcd(a,b)*b;}
inline ll expo(ll b,ll p,ll m){ll res=1; while(p){if(p&1)res=(res*b)%m; b=(b*b)%m; p>>=1;} return res;}
inline ll modinv(ll a,ll m){return expo(a,m-2,m);}

#include "bartender.h"

std::vector<int> BlendWines(int K, std::vector<int> R){
	int N = R.size();
	vector<int> a(N);
	for(int i=0;i<N;i++){
		if(R[i]==N)a[i]=K;
		else a[i]=min(R[i],N-R[i]);
	}
	return a;
}

taster

#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef pair<int,int> ii;
typedef pair<ll,ll> pll;
typedef long double ld;
#define mp make_pair
#define pb push_back
#define fi first
#define se second
#define ALL(x) x.begin(),x.end()
#define SZ(x) (int)x.size()
const int INF=2012345678;
const ll LLINF=4012345678012345678LL;
const ll MOD=1000000007; //998244353; //
const ld PI=3.1415926535898;
const ld EPS=1e-9;
ll gcd(ll a,ll b){if(a<b)swap(a,b);if(b==0)return a;return gcd(b,a%b);}
inline ll lcm(ll a,ll b){return a/gcd(a,b)*b;}
inline ll expo(ll b,ll p,ll m){ll res=1; while(p){if(p&1)res=(res*b)%m; b=(b*b)%m; p>>=1;} return res;}
inline ll modinv(ll a,ll m){return expo(a,m-2,m);}

#include "taster.h"
//int Compare(int P,int Q);

std::vector<int> SortWines(int K, std::vector<int> A) {
	int N = A.size();
	vector<int> ans(N);
	vector<int> c[K+1];
	for(int i=0;i<N;i++){c[A[i]].pb(i);}
	//for(int i=1;i<=K;i++){for(int j:c[i])printf("%d ",j);printf("\n");}
	ans[c[K][0]]=N;
	for(int i=1;i<=K/2;i++){
		if(c[i].empty())continue;
		if(SZ(c[i])==1){
			ans[c[i][0]]=(N-1)/2;
		}else{
			int x=Compare(c[i][0],c[i][1]);
			if(x<0){
				ans[c[i][0]]=i;
				ans[c[i][1]]=N-i;
			}else{
				ans[c[i][0]]=N-i;
				ans[c[i][1]]=i;
			}
		}
	}
	return ans;
}

• Subtask 1: 0 / 100