This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <algorithm>
#include <bitset>
#include <cassert>
#include <chrono>
#include <cmath>
#include <complex>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <ctime>
#include <deque>
#include <functional>
#include <iomanip>
#include <iostream>
#include <iterator>
#include <limits>
#include <list>
#include <map>
#include <numeric>
#include <queue>
#include <random>
#include <ratio>
#include <set>
#include <sstream>
#include <stack>
#include <string>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>
#include <climits>
// #include <ext/pb_ds/assoc_container.hpp>
// #include <ext/pb_ds/assoc_container.hpp>
// #include <ext/pb_ds/trie_policy.hpp>
#define ll long long
#define ld long double
#define mp make_pair
#define pb push_back
#define in insert
#define vll vector<ll>
#define endl "\n"
#define pll pair<ll,ll>
#define f first
#define s second
#define int ll
#define sz(x) (ll)x.size()
#define all(x) (x.begin(),x.end())
using namespace std;
// using namespace __gnu_pbds;
// typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update> os;
const ll INF = 1e12;
const ll N =(1e5+5); // TODO : change value as per problem
const ll MOD = 1e9+7;
struct nice
{
ll x;
ll g;
ll e;
};
nice a[N];
ll gold[N];
ll energy[N];
bool cmp(nice b, nice c){
return (b.x < c.x);
}
void solve(){
ll n;
cin >> n;
for(int i =1;i<=n;i++){
cin >> a[i].x >> a[i].g >> a[i].e;
gold[i] = gold[i-1] + a[i].g;
energy[i] = energy[i-1] + a[i].e;
}
sort(a+1,a+n+1,cmp);
ll ans = 0;
for(ll l = 1;l<=n;l++){
for(ll r = l;r<=n;r++){
ll tote = energy[r]-energy[l-1];
if(tote >= (a[r].x-a[l].x)){
ans = max(gold[r]-gold[l-1],ans);
}
}
}
cout << ans << endl;
}
signed main(){
ios_base::sync_with_stdio(0);
cin.tie(NULL);
ll tt=1;
// cin >> tt;
while(tt--){
solve();
}
}
/*
Pick a Range [L,R] such that :
a) The sum of energy levels in the range >= R-L+1
b) Sum of Gold is maximal Possible
*/
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