Submission #246200

#	Time	Username	Problem	Language	Result	Execution time	Memory
246200		b00n0rp	Cloud Computing (CEOI18_clo)	C++17	100 / 100	2262 ms	3872 KiB

clo

// --------------------------------------------------<TEMPLATE>--------------------------------------------------
// --------------------<optimizations>--------------------
#pragma GCC optimize("Ofast,unroll-loops")
/* I don't understand these pragmas at all. 
   Earlier I added all the optimizations I could find but 
   upon my short amount of testing, these 2 are enough and adding more makes it slower. */
 
// -------------------</optimizations>--------------------
 
// ---------------<Headers and namespaces>----------------
#include <algorithm>
#include <bitset>
#include <cassert>
#include <chrono>
#include <cmath>
#include <complex>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <ctime>
#include <deque>
#include <functional>
#include <iomanip>
#include <iostream>
#include <iterator>
#include <limits>
#include <list>
#include <map>
#include <numeric>
#include <queue>
#include <random>
#include <ratio>
#include <set>
#include <sstream>
#include <stack>
#include <string>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>
using namespace std;
 
/*
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/rope>
using namespace __gnu_pbds;
using namespace __gnu_cxx;
*/
 
// ---------------</Headers and namespaces>---------------
 
// -----------------<Defines and typedefs>----------------
// typedef tree<int,null_type,less<int>,rb_tree_tag, \
tree_order_statistics_node_update> indexed_set; // use less_equal for multiset
// order_of_key (val): returns the no. of values less than val
// find_by_order (k): returns the iterator to kth largest element.(0-based)
 
typedef long double LD;
typedef long long ll;
#define int ll
#define pb push_back
#define mp make_pair
#define REP(i,n) for (int i = 0; i < n; i++)
#define FOR(i,a,b) for (int i = a; i < b; i++)
#define REPD(i,n) for (int i = n-1; i >= 0; i--)
#define FORD(i,a,b) for (int i = a; i >= b; i--)
#define remax(a,b) a = max(a,b)
#define remin(a,b) a = min(a,b)
#define all(v) v.begin(),v.end()
typedef map<int,int> mii;
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef pair<int,int> pii;
typedef vector<pii> vpii;
#define F first
#define S second
#define PQ(type) priority_queue<type>
#define PQD(type) priority_queue<type,vector<type>,greater<type> >
#define ITR :: iterator it
#define WL(t) while(t --)
#define SZ(x) ((int)(x).size())
#define runtime() ((double)clock() / CLOCKS_PER_SEC)
#define TR(container,it) for(typeof(container.begin()) it=container.begin();it!=container.end();it++)
#define sqr(x) ((x)*(x))
#define inrange(i,a,b) ((i>=min(a,b)) && (i<=max(a,b)))
 
// -----<SCANF>-----
#define sfi(x) scanf("%d",&x);
#define sfi2(x,y) scanf("%d%d",&x,&y);
#define sfi3(x,y,z) scanf("%d%d%d",&x,&y,&z);
 
#define sfl(x) scanf("%lld",&x);
#define sfl2(x,y) scanf("%lld%lld",&x,&y);
#define sfl3(x,y,z) scanf("%lld%lld%lld",&x,&y,&z);
#define sfl4(x,y,z,x1) scanf("%lld%lld%lld%lld",&x,&y,&z,&x1);
#define sfl5(x,y,z,x1,y1) scanf("%lld%lld%lld%lld%lld",&x,&y,&z,&x1,&y1);
#define sfl6(x,y,z,x1,y1,z1) scanf("%lld%lld%lld%lld%lld%lld",&x,&y,&z,&x1,&y1,&z1);
 
#define sfs(x) scanf("%s",x);
#define sfs2(x,y) scanf("%s%s",x,y);
#define sfs3(x,y,z) scanf("%s%s%s",x,y,z);
// ----</SCANF>-----
 
// ----<PRINTF>-----
#define pfi(x) printf("%d\n",x);
#define pfi2(x,y) printf("%d %d\n",x,y);
#define pfi3(x,y,z) printf("%d %d %d\n",x,y,z);
 
#define pfl(x) printf("%lld\n",x);
#define pfl2(x,y) printf("%lld %lld\n",x,y);
#define pfl3(x,y,z) printf("%lld %lld %lld\n",x,y,z);
 
#define pfs(x) printf("%s\n",x);
#define pfs2(x,y) printf("%s %s\n",x,y);
#define pfs3(x,y,z) printf("%s %s %s\n",x,y,z);
 
#define pwe(x) printf("%lld ",x); // print without end
// ----</PRINTF>----
 
#define FLSH fflush(stdout)
#define fileIO(name) \
    freopen(name".in", "r", stdin); \
    freopen(name".out", "w", stdout);
#define PRECISION(x) cout << fixed << setprecision(x); 
#define FAST_IO ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
 
// ----------------</Defines and typedefs>----------------
 
// -------------------<Debugging stuff>-------------------
#define TRACE
 
#ifdef TRACE
#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)
template <typename Arg1>
void __f(const char* name, Arg1&& arg1){
    cerr << name << " : " << arg1 << std::endl;
}
template <typename Arg1, typename... Args>
void __f(const char* names, Arg1&& arg1, Args&&... args){
    const char* comma = strchr(names + 1, ',');cerr.write(names, comma - names) << " : " << arg1<<" | ";__f(comma+1, args...);
}
#else
#define trace(...)
#endif
 
// ------------------</Debugging stuff>-------------------
 
// ------------------------<Consts>-----------------------
const int MAXN = 200105;
const int SQRTN = 1003;
const int LOGN = 22;
const double PI=acos(-1);
 
#ifdef int
const int INF=1e16;
#else
const int INF=1e9;
#endif
 
const int MOD = 1000000007;
const int FMOD = 998244353;
const double eps = 1e-9;
 
// -----------------------</Consts>-----------------------
 
// -------------------------<RNG>-------------------------
mt19937 RNG(chrono::steady_clock::now().time_since_epoch().count()); 
#define SHUF(v) shuffle(all(v), RNG);
// Use mt19937_64 for 64 bit random numbers.
 
// ------------------------</RNG>-------------------------
 
// ----------------------<MATH>---------------------------
template<typename T> T gcd(T a, T b){return(b?__gcd(a,b):a);}
template<typename T> T lcm(T a, T b){return(a*(b/gcd(a,b)));}
int add(int a, int b, int c = MOD){int res=a+b;return(res>=c?res-c:res);}
int mod_neg(int a, int b, int c = MOD){int res;if(abs(a-b)<c)res=a-b;else res=(a-b)%c;return(res<0?res+c:res);}
int mul(int a, int b, int c = MOD){ll res=(ll)a*b;return(res>=c?res%c:res);}
int muln(int a, int b, int c = MOD){ll res=(ll)a*b;return ((res%c)+c)%c;}
ll mulmod(ll a,ll b, ll m = MOD){ll q = (ll)(((LD)a*(LD)b)/(LD)m);ll r=a*b-q*m;if(r>m)r%=m;if(r<0)r+=m;return r;}
template<typename T>T expo(T e, T n){T x=1,p=e;while(n){if(n&1)x=x*p;p=p*p;n>>=1;}return x;}
template<typename T>T power(T e, T n, T m = MOD){T x=1,p=e;while(n){if(n&1)x=mul(x,p,m);p=mul(p,p,m);n>>=1;}return x;}
template<typename T>T extended_euclid(T a, T b, T &x, T &y){T xx=0,yy=1;y=0;x=1;while(b){T q=a/b,t=b;b=a%b;a=t;\
t=xx;xx=x-q*xx;x=t;t=yy;yy=y-q*yy;y=t;}return a;}
template<typename T>T mod_inverse(T a, T n = MOD){T x,y,z=0;T d=extended_euclid(a,n,x,y);return(d>1?-1:mod_neg(x,z,n));}
 
const int FACSZ = 1; // Make sure to change this
 
int fact[FACSZ],ifact[FACSZ];
 
void precom(int c = MOD){
    fact[0] = 1;
    FOR(i,1,FACSZ) fact[i] = mul(fact[i-1],i,c);
    ifact[FACSZ-1] = mod_inverse(fact[FACSZ-1],c);
    REPD(i,FACSZ-1){
        ifact[i] = mul(i+1,ifact[i+1],c);
    }
}
 
int ncr(int n,int r,int c = MOD){
    return mul(mul(ifact[r],ifact[n-r],c),fact[n],c);
} 
// ----------------------</MATH>--------------------------
// --------------------------------------------------</TEMPLATE>--------------------------------------------------
 
void solvethetestcase();
 
signed main(){
    // (UNCOMMENT FOR CIN/COUT) \
    FAST_IO
    PRECISION(10)
 
    int t = 1;
    // (UNCOMMENT FOR MULTIPLE TEST CASES) \
    sfl(t);
    FOR(testcase,1,t+1){
        // (UNCOMMENT FOR CODEJAM) \
        printf("Case #%lld: ",testcase); 
        solvethetestcase();
    }
}   
 
int n,m;
vector<pair<pii,pii> > a;
int dp[MAXN];
int new_dp[MAXN];
// {{clock rate,type},{cores,value}}
 
void solvethetestcase(){
    sfl(n)
    REP(i,n){
        int c,f,v;
        sfl3(c,f,v)
        a.pb({{-f,0},{c,v}});
    }
    sfl(m)
    REP(i,m){
        int c,f,v;
        sfl3(c,f,v) 
        a.pb({{-f,1},{c,v}});
    }
    sort(all(a));
    REP(i,MAXN) dp[i] = -INF;
    dp[0] = 0;
    REP(i,n+m){
        if(!a[i].F.S) REP(j,MAXN){
            new_dp[j] = dp[j];
            if(j >= a[i].S.F and dp[j-a[i].S.F]-a[i].S.S > dp[j]) new_dp[j] = dp[j-a[i].S.F]-a[i].S.S;
        }
        else REP(j,MAXN){
            new_dp[j] = dp[j];
            if(j+a[i].S.F < MAXN and dp[j+a[i].S.F]+a[i].S.S > dp[j]) new_dp[j] = dp[j+a[i].S.F]+a[i].S.S;
        }
        FORD(j,MAXN-2,0) remax(new_dp[j],new_dp[j+1]);
        REP(j,MAXN) dp[j] = new_dp[j];
        // trace(i,a[i].F.F,a[i].F.S,a[i].S.F,a[i].S.S);
        // REP(j,10) trace(j,new_dp[j]);
        
    }
    pfl(dp[0])
}

Compilation message (stderr)

clo.cpp:54:1: warning: multi-line comment [-Wcomment]
 // typedef tree<int,null_type,less<int>,rb_tree_tag, \
 ^
clo.cpp:210:5: warning: multi-line comment [-Wcomment]
     // (UNCOMMENT FOR CIN/COUT) \
     ^
clo.cpp:215:5: warning: multi-line comment [-Wcomment]
     // (UNCOMMENT FOR MULTIPLE TEST CASES) \
     ^
clo.cpp:218:9: warning: multi-line comment [-Wcomment]
         // (UNCOMMENT FOR CODEJAM) \
         ^
clo.cpp: In function 'void solvethetestcase()':
clo.cpp:93:21: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
 #define sfl(x) scanf("%lld",&x);
                ~~~~~^~~~~~~~~~~
clo.cpp:231:5: note: in expansion of macro 'sfl'
     sfl(n)
     ^~~
clo.cpp:95:26: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
 #define sfl3(x,y,z) scanf("%lld%lld%lld",&x,&y,&z);
                     ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~
clo.cpp:234:9: note: in expansion of macro 'sfl3'
         sfl3(c,f,v)
         ^~~~
clo.cpp:93:21: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
 #define sfl(x) scanf("%lld",&x);
                ~~~~~^~~~~~~~~~~
clo.cpp:237:5: note: in expansion of macro 'sfl'
     sfl(m)
     ^~~
clo.cpp:95:26: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
 #define sfl3(x,y,z) scanf("%lld%lld%lld",&x,&y,&z);
                     ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~
clo.cpp:240:9: note: in expansion of macro 'sfl3'
         sfl3(c,f,v) 
         ^~~~

• Subtask 1: 18 / 18
• Subtask 2: 18 / 18
• Subtask 3: 18 / 18
• Subtask 4: 18 / 18
• Subtask 5: 18 / 18
• Subtask 6: 10 / 10