Submission #244252

#	Time	Username	Problem	Language	Result	Execution time	Memory
244252		tleontest1	Wall (IOI14_wall)	C++14	100 / 100	1726 ms	105636 KiB

wall

#include "wall.h"
#pragma GCC optimize ("O3")
#pragma GCC target ("sse4")
#pragma GCC optimize ("unroll-loops")
#pragma GCC target ("avx2")
 
#include <bits/stdc++.h>
 
using namespace std;
 
typedef long long lo;
typedef pair< int,int > PII;
typedef pair< int,PII > PIII;
 
#define fi first
#define se second
#define mp make_pair
#define endl "\n"
#define pb push_back
#define fio() ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL)
#define FOR for(int i=1;i<=n;i++)
#define mid ((start+end)/2)
#define ort ((bas+son)/2)
 
const int inf = 1000000000;
const lo KOK = 100000;
const lo LOG = 30;
const lo li = 2000005;
const lo mod = 1000000007;
 
int flag,t,m,tree[li*4],lazy1[li*4],lazy[li*4];
int cev;
//~ PIII lazy[li*4];
 
inline void push(int node,int start,int end){
	{tree[node]=max(tree[node],lazy[node]);}
	{tree[node]=min(tree[node],lazy1[node]);}
	if(start!=end){
		lazy[node*2] = max(lazy[node*2],lazy[node]),lazy1[node*2] = max(lazy1[node*2],lazy[node]);
        lazy[node*2+1] = max(lazy[node*2+1],lazy[node]),lazy1[node*2+1] = max(lazy1[node*2+1],lazy[node]);
        lazy1[node*2] = min(lazy1[node*2],lazy1[node]),lazy[node*2] = min(lazy[node*2],lazy1[node]);
        lazy1[node*2+1] = min(lazy1[node*2+1],lazy1[node]),lazy[node*2+1] = min(lazy[node*2+1],lazy1[node]);
	}
	lazy[node]=-inf;
	lazy1[node]=inf;
}
 
inline void update(int node,int start,int end,int l,int r,int val,int ty){
	//~ push1(node,start,end);
	push(node,start,end);
	if(start>end || start>r || end<l)return ;
	
	if(start>=l && end<=r){
		//~ cout<<query1(1,1,m,start,start)<<" : : "<<query1(1,1,m,end,end)<<" : : "<<start<<" ; : "<<end<<endl;;
		if(ty==1)lazy[node]=max(val,lazy[node]);
		if(ty==2)lazy1[node]=min(lazy1[node],val);
		//~ push1(node,start,end);
		push(node,start,end);
		return ;
	}
	update(node*2,start,mid,l,r,val,ty);
	update(node*2+1,mid+1,end,l,r,val,ty);
	tree[node]=max(tree[node*2],tree[node*2+1]);
}
 
inline int query(int node,int start,int end,int l,int r){
	if(start>end || start>r || end<l)return 0;
	push(node,start,end);
	//~ push1(node,start,end);
	if(start>=l && end<=r)return tree[node];
	return max(query(node*2,start,mid,l,r),query(node*2+1,mid+1,end,l,r));
}
 
void buildWall(int n, int k, int op[], int left[], int right[], int height[], int finalHeight[]){
	m=n;
	for(int i=1;i<=4*n;i++){
		//~ tree1[i]=inf;
		lazy1[i]=inf;
		//~ tree[i]=-1;
		lazy[i]=-inf;
		//~ tree2[i]=inf;
		//~ lazy2[i]=inf;
	}
	//~ int mn=inf;
	//~ for(int i=k-1;i>=0;i--){
		//~ if(op[i]==1)
		//~ update2(1,1,n,left[i],right[i],i);
	//~ }
	//~ FOR{
		//~ int at=query2(1,1,n,i,i);
		//~ cout<<i<<" : : "<<at<<endl;
		//~ if(at==inf)continue;
		//~ v[at].pb(i);
	//~ }
	for(int i=0;i<k;i++){
		//~ cout<<height[i]<<endl;
		//~ if(op[i]==2){
			//~ update1(1,1,n,left[i]+1,right[i]+1,height[i]);
			//~ continue;
		//~ }
		//~ cout<<"**\n";
		update(1,1,n,left[i]+1,right[i]+1,height[i],op[i]);
		//~ for(int j=0;j<(int)v[i].size();j++){
			//~ cout<<v[i][j]<<endl;
		//~ }
		//~ if(op[i]==2)update1(1,1,n,left[i]+1,right[i]+1,height[i]);
		//~ update2(1,1,n,left[i]+1,right[i]+1,i);
	}
	FOR finalHeight[i-1]=query(1,1,n,i,i);
	return;
}

• Subtask 1: 8 / 8
• Subtask 2: 24 / 24
• Subtask 3: 29 / 29
• Subtask 4: 39 / 39