Submission #243864

#	Time	Username	Problem	Language	Result	Execution time	Memory
243864		Leonardo_Paes	Jakarta Skyscrapers (APIO15_skyscraper)	C++17	36 / 100	133 ms	197312 KiB

skyscraper

#include <bits/stdc++.h>
using namespace std;
typedef pair<int,int> pii;
typedef pair<int,pii> pip;
#define f first
#define s second
const int maxn = 2e4+10, magic = 2500, inf = 0x3f3f3f3f;
int b[maxn], p[maxn], dist1[maxn], dist2[maxn][magic+5];
vector<int> doges[maxn];
bool mark[maxn];
int main(){
    ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);
    int n, m;
    cin >> n >> m;
    for(int i=0; i<m; i++){
        cin >> b[i] >> p[i];
        doges[b[i]].push_back(i);
    }
    priority_queue<pip, vector<pip>, greater<pip>> fila;
    memset(dist1, inf, sizeof dist1);
    memset(dist2, inf, sizeof dist2);
    fila.push({0, {b[0], 0}});
    mark[0] = 1;
    while(!fila.empty()){
        int d = fila.top().f, u = fila.top().s.f, id = fila.top().s.s, power = p[fila.top().s.s];
        fila.pop();
        if(power <= magic){
            if(dist2[u][power] == inf) dist2[u][power] = d;
            if(u + power < n and dist2[u + power][power] == inf){
                fila.push({d + 1, {u + power, id}});
                dist2[u + power][power] = d + 1;
            }
            if(u - power >= 0 and dist2[u - power][power] == inf){
                fila.push({d + 1, {u - power, id}});
                dist2[u - power][power] = d + 1;
            }
        }
        else{
            if(dist1[u] == inf) dist1[u] = d;
            if(mark[id]) continue;
            mark[id] = 1;
            for(int v=u+power, qtd=1; v<n; v+=power, qtd++) fila.push({d + qtd, {v, id}});
            for(int v=u-power, qtd=1; v>=0; v-=power, qtd++) fila.push({d + qtd, {v, id}});
        }
        if(!doges[u].empty()){
            for(auto v : doges[u]) fila.push({d, {u, v}});
            doges[u].clear();
        }
    }
    int ans = dist1[b[1]];
    for(int i=1; i<=magic; i++) ans = min(ans, dist2[b[1]][i]);
    cout << (ans == inf ? -1 : ans) << "\n";
    return 0;
}

• Subtask 1: 10 / 10
• Subtask 2: 12 / 12
• Subtask 3: 14 / 14
• Subtask 4: 0 / 21
• Subtask 5: 0 / 43