Submission #243497

#	Time	Username	Problem	Language	Result	Execution time	Memory
243497		VEGAnn	Zoltan (COCI16_zoltan)	C++14	42 / 140	1100 ms	12284 KiB

zoltan

#include <bits/stdc++.h>
//#pragma GCC optimize("unroll-loops")
//#pragma GCC optimize("-O3")
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize("fast-math")
//#pragma GCC optimize("no-stack-protector")
#define all(x) x.begin(),x.end()
#define sz(x) ((int)x.size())
#define i2 array<int,2>
#define PB push_back
using namespace std;
const int N = 2010;
const int oo = 2e9;
const int md = int(1e9) + 7;
i2 f[N][N][2], ans, cur;
vector<int> vc;
int n, a[N];

void SUM(int &x, int y){
    x += y;
    if (x >= md)
        x -= md;
}

void upd(i2 &cr, i2 nw){
    if (nw[0] > cr[0])
        cr = nw; else
    if (nw[0] == cr[0]){
        SUM(cr[1], nw[1]);
    }
}

int main(){
    ios_base::sync_with_stdio(0); cin.tie(0);

#ifdef _LOCAL
    freopen("in.txt","r",stdin);
#endif // _LOCAL

    cin >> n;

    assert(n <= 1000);

    for (int i = 0; i < n; i++) {
        cin >> a[i];
        vc.PB(a[i]);
    }

    sort(all(vc));
    vc.resize(unique(all(vc)) - vc.begin());

    for (int i = 0; i < n; i++)
        a[i] = lower_bound(all(vc), a[i]) - vc.begin();

    f[a[0]][a[0]][0] = {1, 1};

    int mn = a[0], mx = a[0];

    int po = 1;

    for (int i = 1; i < n; i++){
        int tp = (i & 1);

        SUM(po, po);

        mn = min(mn, a[i]);
        mx = max(mx, a[i]);

        for (int men = mn;  men <= mx; men++)
        for (int mex = men; mex <= mx; mex++)
            f[men][mex][tp] = {0, 0};

        f[a[i]][a[i]][tp] = {1, po};

        for (int men = mn;  men <= mx; men++)
        for (int mex = men; mex <= mx; mex++){
            if (f[men][mex][tp ^ 1][0] == 0) continue;

            upd(f[men][mex][tp], f[men][mex][tp ^ 1]);
            upd(f[men][mex][tp], f[men][mex][tp ^ 1]);

            cur = f[men][mex][tp ^ 1];
            cur[0]++;

            if (a[i] < men)
                upd(f[a[i]][mex][tp], cur);

            if (a[i] > mex)
                upd(f[men][a[i]][tp], cur);
        }
    }

    int tp = ((n - 1) & 1);

    for (int i = mn; i <= mx; i++)
    for (int j = i; j <= mx; j++)
        upd(ans, f[i][j][tp]);

    cout << ans[0] << " " << ans[1];

    return 0;
}

• Subtask 1: 42 / 140