Submission #241404

#	Time	Username	Problem	Language	Result	Execution time	Memory
241404		abacaba	Holiday (IOI14_holiday)	C++14	0 / 100	5096 ms	1692 KiB

holiday

#include <iostream>
#include <string>
#include <unordered_map>
#include <unordered_set>
#include <cstring>
#include <chrono>
#include <vector>
#include "holiday.h"
#include <map>
#include <random>
#include <set>
#include <algorithm>
#include <math.h>
#include <cstdio>
#include <stdio.h>
#include <queue>
#include <bitset>
#include <cstdlib>
#include <deque>
#include <cassert>
#include <stack>
using namespace std;

#define mp make_pair
#define f first
#define se second
#define pb push_back
#define ppb pop_back
#define emb emplace_back
#define ll long long
#define ull unsigned long long
#define cntbit(x) __builtin_popcount(x)
#define endl '\n'
#define uset unordered_set
#define umap unordered_map
#define pii pair<int, int>
#define ld long double
#define pll pair<long long, long long>

mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());

template <typename T> inline T range(T l, T r) {
    return uniform_int_distribution<T>(l, r)(rng);
}

inline void setin(string s) {
    freopen(s.c_str(), "r", stdin);
}

inline void setout(string s) {
    freopen(s.c_str(), "w", stdout);
}

template <typename T> void Min(T &a, T b) {
    a = min(a, b);
}

template <typename T> void Max(T &a, T b) {
    a = max(a, b);
}

const int inf = 0x3f3f3f3f;
const int mod = 998244353;
const int N = 1e5 + 15;
int a[N];

inline ll get(int num, vector <int> now) {
    sort(now.rbegin(), now.rend());
    if(num <= 0)
        return 0;
    ll sum = 0;
    for(int k = 0; k < min((int)now.size(), num); ++k)
        sum += now[k];
    return sum;
}

long long findMaxAttraction(int n, int start, int d, int attraction[]) {
    for(int i = 0; i < n; ++i)
        a[i] = attraction[i];
    ll ans = 0;
    for(int i = start; i < n; ++i) {
        vector <int> now = {};
        for(int j = start; j <= i; ++j)
            now.pb(a[j]);
        Max(ans, get(d - (i - start), now));
        for(int j = start - 1; j >= 0; --j) {
            now.pb(a[j]);
            Max(ans, get(d - (i - j) - (i - start), now));
        }
    }
    return ans;
}

• Subtask 1: 0 / 7
• Subtask 2: 0 / 23
• Subtask 3: 0 / 17
• Subtask 4: 0 / 53