Submission #240725

#TimeUsernameProblemLanguageResultExecution timeMemory
240725WhaleVomitLightning Conductor (POI11_pio)C++14
100 / 100
822 ms24984 KiB
#include <bits/stdc++.h> using namespace std; #define f first #define s second #define pb push_back #define mp make_pair #define all(v) v.begin(), v.end() #define sz(v) (int)v.size() #define MOO(i, a, b) for(int i=a; i<b; i++) #define M00(i, a) for(int i=0; i<a; i++) #define MOOd(i,a,b) for(int i = (b)-1; i >= a; i--) #define M00d(i,a) for(int i = (a)-1; i>=0; i--) #define FAST ios::sync_with_stdio(0); cin.tie(0); #define finish(x) return cout << x << '\n', 0; #define dbg(x) cerr << ">>> " << #x << " = " << x << "\n"; #define _ << " _ " << typedef long long ll; typedef long double ld; typedef vector<int> vi; typedef pair<int,int> pi; typedef pair<ld,ld> pd; typedef complex<ld> cd; const int MAX_N = 500500; int n; ld eval(ld x, pair<ll,ll> curve) { return curve.s + sqrt(curve.f - x); } ll evalLong(ll x, pair<ll,ll> curve) { // ceil(eval(x, curve)) ld y = eval(x,curve); ll y1 = y; if((y1-curve.s)*(y1-curve.s) >= curve.f-x) return y1; return y1+1; } ld intersect(pair<ll,ll> c1, pair<ll,ll> c2) { // c2 comes after c1 if(eval(c1.f, c2) <= c1.s) return c1.f; if(eval(0, c2) >= eval(0, c1)) return -1; ld lo = 0; ld hi = c1.f; while(hi-lo > 1e-8) { ld mid = (lo + hi)/2; if(eval(mid, c1) < eval(mid, c2)) { hi = mid; } else { lo = mid; } } assert(0 <= lo && lo < c1.f); return lo; } vector<ll> solve(vector<ll> v) { deque<pair<ll,ll>> dq; MOO(i, 1, n) { pair<ll,ll> curve = mp(i, v[i]); while(1) { if(dq.empty()) break; else if(intersect(dq[sz(dq)-1], curve) < 0) dq.pop_back(); else { if(sz(dq) >= 2) { if(intersect(dq[sz(dq)-2], curve) < intersect(dq[sz(dq)-2], dq[sz(dq)-1])) { dq.pop_back(); } else { break; } } else { break; } } } dq.pb(curve); } vector<ll> ans; M00(i, n-1) { while(dq[0].f <= i) dq.pop_front(); while(sz(dq) >= 2 && eval(i, dq[1]) > eval(i, dq[0])) dq.pop_front(); ans.pb(max(0LL,evalLong(i, dq[0])-v[i])); } ans.pb(-1); return ans; } int main() { FAST cin >> n; vector<ll> arr(n); M00(i, n) cin >> arr[i]; vector<ll> res1 = solve(arr); reverse(all(arr)); vector<ll> res2 = solve(arr); reverse(all(res2)); M00(i, n) { cout << max(res1[i], res2[i]) << "\n"; } }
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