Submission #239663

#	Time	Username	Problem	Language	Result	Execution time	Memory
239663		Vimmer	Timovi (COCI18_timovi)	C++14	40 / 80	30 ms	5888 KiB

timovi

#include <bits/stdc++.h>
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>

//#pragma GCC optimize("unroll-loops")
//#pragma GCC optimize("-O3")
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize("fast-math")
//#pragma GCC optimize("no-stack-protector")

#define F first
#define S second
#define sz(x) int(x.size())
#define pb push_back
#define N 101001
#define M ll(1e9 + 7)
#define inf 1e9 + 1e9


using namespace std;
//using namespace __gnu_pbds;

typedef long double ld;
typedef long long ll;
typedef short int si;
typedef array <int, 3> a3;

//typedef tree <int, null_type, less_equal<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;


ll calc(ll n, ll k, ll x) {return (n - 1) * k * x + n * k;}

int main()
{
    //freopen("input.txt", "r", stdin); //freopen("output4.txt", "w", stdout);

    ios_base::sync_with_stdio(0); istream::sync_with_stdio(0); cin.tie(0); cout.tie(0);

    ll n, m, k;

    cin >> n >> k >> m;

    ll l = 1, r = m;

    while (l + 1 < r)
    {
        ll md = (l + r) >> 1;

        if (m >= calc(n, k, md)) l = md; else r = md;
    }

    while (calc(n, k, l + 1) <= m) l++;

    while (calc(n, k, l) > m) l--;

    if (l == -1)
    {
        for (int i = 0; i < n; i++)
        {
            if (m >= k)
            {
                cout << k << " ";

                m -= k;
            }
            else
            {
                cout << m << " ";

                m = 0;
            }
        }

        exit(0);
    }

    ll ost = m - calc(n, k, l);

    ll a[n];

    for (int i = 0; i < n; i++)
    {
       ll sum = k;

       if (l % 2) {
            if (ost >= k)
            {
                sum += k;

                ost -= k;
            }
            else
            {
                sum += ost;

                ost = 0;
            }
       }
        if (i == 0) sum += ((l + 1) / 2) * k;
          else if (i == n - 1) sum += (l / 2) * k;
            else sum += l * k;

        a[i] = sum;
    }

    if (l % 2 == 0)
        for (int i = n - 2; i >= 0; i--)
        {
             if (ost >= k)
            {
                a[i] += k;

                ost -= k;
            }
            else
            {
                a[i] += ost;

                ost = 0;
            }
        }

    for (int i = 0; i < n; i++) cout << a[i] << " ";
}

• Subtask 1: 40 / 80