Submission #239343

#TimeUsernameProblemLanguageResultExecution timeMemory
239343nicolaalexandraAliens (IOI16_aliens)C++14
25 / 100
56 ms63144 KiB
#include <bits/stdc++.h> #include "aliens.h" #define DIMN 100010 #define DIMM 1000010 #define INF 1000000000000000LL using namespace std; int n,k,m,i,j,x,y; vector <int> r,c; long long dp[DIMN][2]; pair <int, int> v[DIMN]; struct dreapta{ long long a,b; } aint[DIMM*4]; long long f (long long a, long long b, int x){ return a*x + b; } void add (int nod, int st, int dr, long long a, long long b){ if (st == dr){ if (f(a,b,st) < f(aint[nod].a,aint[nod].b,st)) aint[nod] = {a,b}; return; } int mid = (st+dr)>>1; int ok_mid = 0, ok_dr = 0; if (f(a,b,mid) <= f(aint[nod].a,aint[nod].b,mid)) ok_mid = 1; if (f(a,b,dr) <= f(aint[nod].a,aint[nod].b,dr)) ok_dr = 1; if (!ok_mid && !ok_dr) add (nod<<1,st,mid,a,b); else { if (!ok_mid && ok_dr) add ((nod<<1)|1,mid+1,dr,a,b); else { swap (aint[nod].a,a); swap (aint[nod].b,b); if (ok_dr) add (nod<<1,st,mid,a,b); else add ((nod<<1)|1,mid+1,dr,a,b); }}} long long query (int nod, int st, int dr, int x){ if (st == dr) return f(aint[nod].a,aint[nod].b,x); int mid = (st+dr)>>1; long long sol = INF; if (x <= mid) sol = query (nod<<1,st,mid,x); else sol = query ((nod<<1)|1,mid+1,dr,x); return min (sol,f(aint[nod].a,aint[nod].b,x)); } long long patrat (long long x){ return x*x; } long long modul (long long x){ return max (x,-x); } inline int cmp (pair<int,int> a, pair<int,int> b){ if (a.first == b.first) return a.second > b.second; return a.first < b.first; } long long take_photos (int N, int m, int K, std::vector <int> r, std::vector <int> c){ n = N, k = K; for (i=0;i<n;i++) v[i+1] = make_pair(min(r[i],c[i]),max(r[i],c[i])); sort (v+1,v+n+1,cmp); /// elimin intervalele care sunt incluse in altele int st = -1, dr = -1, el = 0; for (i=1;i<=n;i++){ if (!(v[i].first >= st && v[i].second <= dr)){ v[++el] = v[i]; st = v[i].first, dr = v[i].second; } } n = el; /// dp[i][j] - costul minim sa parcurg primele i puncte si sa am j subsecvente for (i=1;i<=n;i++) dp[i][1] = patrat (v[i].second - v[1].first + 1); int t = 0; for (j=2;j<=min(n,k);j++){ for (i=1;i<=4*m+4;i++) aint[i] = {INF,INF}; for (i=j;i<=n;i++){ add (1,1,m,-2*v[i].first,dp[i-1][1-t] + patrat(v[i].first) - patrat(max(0,v[i-1].second - v[i].first + 1))); dp[i][t] = dp[i][1-t]; dp[i][t] = min(dp[i][t], patrat(v[i].second + 1) + query (1,1,m,v[i].second+1)); } t = 1-t; } return dp[n][1-t]; }
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