| # | Time | Username | Problem | Language | Result | Execution time | Memory | 
|---|---|---|---|---|---|---|---|
| 239017 | kartel | Mate (COCI18_mate) | C++14 | 1935 ms | 19624 KiB | 
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>
#define in(x) freopen(x, "r", stdin)
#define out(x) freopen(x, "w", stdout)
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
#pragma GCC optimize("-O3")
#define F first
#define S second
#define pb push_back
#define N +100500
#define M ll(1e9 + 7)
#define sz(x) (int)x.size()
#define re return
#define oo ll(1e9)
#define el '\n'
#define pii pair <int, int>
using namespace std;
//using namespace __gnu_pbds;
//typedef tree <int, null_type, less_equal <int> , rb_tree_tag, tree_order_statistics_node_update> ordered_set;
typedef long long ll;
typedef long double ld;
int sf[N][26], i, n, q, len, fc[N], j, ans = 0;
int c[2005][2005];
string s, t;
int sum(int x, int y) {return (x + y) % M;}
int mult(int x, int y) {return (x * 1ll * y) % M;}
int bp(int x, int y)
{
    if (y == 0) return 1;
    if (y % 2) return (mult(x, bp(x, y - 1)));
    int a = bp(x, y / 2);
    return mult(a, a);
}
int C(int k, int n)
{
    return c[n][k];
}
int main()
{
    srand(time(0));
    ios_base::sync_with_stdio(0);
    iostream::sync_with_stdio(0);
    ios::sync_with_stdio(0);
    cin.tie(NULL);
    cout.tie(NULL);
//    in("input.txt");
//    out("output.txt");
    cin >> s;
    cin >> q;
    n = sz(s);
    for (i = n - 1; i >= 0; i--)
    {
        for (j = 0; j < 26; j++) sf[i][j] = sf[i + 1][j];
        sf[i][s[i] - 'a']++;
    }
    for (i = 0; i <= n; i++)
    {
        c[i][0] = c[i][i] = 1;
        for (int j = 1; j < i; j++)
            c[i][j] = sum(c[i - 1][j], c[i - 1][j - 1]);
    }
    while (q--)
    {
        cin >> len >> t;
        ans = 0;
        for (i = len - 2; i < n; i++)
        {
            if (s[i] == t[0])
            {
                ans = sum(ans, mult(C(len - 2, i), sf[i + 1][t[1] - 'a']));
            }
        }
        cout << ans << el;
    }
}
/*
8 8
...).).*
*....)..
.)*(..).
(*)((...
.)).)(..
.)(.)..(
...).(.*
M.......
*/
//
//110000
//1100
| # | Verdict | Execution time | Memory | Grader output | 
|---|---|---|---|---|
| Fetching results... | ||||
