# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
238388 | ant101 | Bob (COCI14_bob) | C++14 | 193 ms | 25860 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <iostream>
#include <algorithm>
#include <cstring>
#include <iomanip>
#include <fstream>
#include <cmath>
#include <vector>
#include <set>
#include <unordered_set>
#include <unordered_map>
#include <map>
#include <stack>
#include <queue>
#include <assert.h>
#include <limits>
#include <cstdio>
using namespace std;
//#define RDEBUG 1
#ifdef RDEBUG
#define D(x) x
#else
#define D(x)
#endif
#define inf 0x7fffffff
#define MOD 1000000007
typedef long long ll;
ll add(ll a, ll b) {
a += b;
if(a >= MOD) {
a -= MOD;
}
return a;
}
ll sub(ll a, ll b) {
a -= b;
if(a < 0) {
a += MOD;
}
return a;
}
ll mul(ll a, ll b) {
return (a * b)%MOD;
}
void add_self(ll& a, ll b) {
a = add(a, b);
}
void sub_self(ll& a, ll b) {
a = sub(a, b);
}
void mul_self(ll& a, ll b) {
a = mul(a, b);
}
const ll MAXN = 200010;
int main() {
int n , m ;
scanf("%d %d" , &n , &m) ;
int arr[n+2][m+2] , now[n+2][m+2];
for(int i = 1 ; i <= n ; ++i) {
for(int j = 1 ; j <= m ; ++j)
scanf("%d" , &arr[i][j]) ;
}
//prepare now for every element
for(int i = 1 ; i <= n ; ++i) {
now[i][m] = 1ll ;
for(int j = m-1 ; j >= 1 ; --j) {
if(arr[i][j] == arr[i][j+1])
now[i][j] = now[i][j+1] + 1ll;
else
now[i][j] = 1ll;
}
}
long long ans = 0ll ;
long long sol[n+2][m+2] ;
//loop on every column
for(int j = 1 ; j <= m ; ++j) {
arr[0][j] = -1 ;
stack< pair<int , int> >s ;
for(int i = 1 ; i <= n ; ++i) {
pair<int , int>cur ;
cur.first = i , cur.second = 1ll ;
sol[i][j] = 0ll ;
//new value
if(arr[i][j] != arr[i-1][j]) {
while(!s.empty())
s.pop() ;
sol[i][j] = now[i][j] * 1ll;
ans += sol[i][j] ;
s.push(cur) ;
continue ;
}
//loop in stack
while (!s.empty() && now[s.top().first][j] >= now[i][j]) {
pair<int , int>p = s.top() ;
s.pop();
cur.second += p.second ;
}
sol[i][j] = (cur.second * 1ll * now[i][j]) ;
if (s.size() > 0) {
pair<int , int>p = s.top() ;
sol[i][j] += sol[p.first][j] ;
}
ans += sol[i][j] ;
s.push(cur) ;
}
}
return printf("%lld" , ans) , 0 ;
}
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