oj.uz

답안 #237784

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
237784 2020-06-08T18:14:52 Z IgorI Soccer (JOI17_soccer) C++17
30 / 100
 14 ms 384 KB 
const int LG = 21;
const int FN = 400005;
const long long MOD = 998244353;
const long long INF = 1e9;
const long long INFLL = 1e18;

#include <bits/stdc++.h>

using namespace std;

typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<int> vi;
typedef vector<ll> vll;

#define forn(i, n) for (int (i) = 0; (i) != (n); (i)++)
#define all(v) (v).begin(), (v).end()
#define rall(v) (v).rbegin(), (v).rend()
#define popcount(x) __builtin_popcount(x)
#define popcountll(x) __builtin_popcountll(x)
#define fi first
#define se second
#define re return
#define pb push_back
#define uniq(x) sort(all(x)); (x).resize(unique(all(x)) - (x).begin())

#ifdef LOCAL
#define dbg(x) cerr << __LINE__ << " " << #x << " " << x << endl
#define ln cerr << __LINE__ << endl
#else
#define dbg(x) void(0)
#define ln void(0)
#endif // LOCAL

int cx[4] = {-1, 0, 1, 0};
int cy[4] = {0, -1, 0, 1};
string Yes[2] = {"No", "Yes"};
string YES[2] = {"NO", "YES"};

ll inq(ll x, ll y)
{
    if (!y) re 1 % MOD;
    ll l = inq(x, y / 2);
    if (y % 2) re l * l % MOD * x % MOD;
    re l * l % MOD;
}

ll rev(ll x)
{
    return inq(x, MOD - 2);
}

bool __precomputed_combinatorics = 0;
vector<ll> __fact, __ufact, __rev;

void __precompute_combinatorics()
{
    __precomputed_combinatorics = 1;
    __fact.resize(FN);
    __ufact.resize(FN);
    __rev.resize(FN);
    __rev[1] = 1;
    for (int i = 2; i < FN; i++) __rev[i] = MOD - __rev[MOD % i] * (MOD / i) % MOD;
    __fact[0] = 1, __ufact[0] = 1;
    for (int i = 1; i < FN; i++) __fact[i] = __fact[i - 1] * i % MOD, __ufact[i] = __ufact[i - 1] * __rev[i] % MOD;
}

ll fact(int x)
{
    if (!__precomputed_combinatorics) __precompute_combinatorics();
    return __fact[x];
}

ll cnk(int n, int k)
{
    if (k < 0 || k > n) return 0;
    if (!__precomputed_combinatorics) __precompute_combinatorics();
    return __fact[n] * __ufact[n - k] % MOD * __ufact[k] % MOD;
}

int Root(int x, vector<int> &root)
{
    if (x == root[x]) return x;
    return root[x] = Root(root[x], root);
}

void Merge(int v, int u, vector<int> &root, vector<int> &sz)
{
    v = Root(v, root), u = Root(u, root);
    if (v == u) return;
    if (sz[v] < sz[u])
    {
        sz[u] += sz[v];
        root[v] = u;
    }
    else
    {
        sz[v] += sz[u];
        root[u] = v;
    }
}

int ok(int x, int n)
{
    return 0 <= x && x < n;
}

void bfs(int v, vi &dist, vector<vi> &graph)
{
    fill(all(dist), -1);
    dist[v] = 0;
    vi q = {v};
    for (int i = 0; i < q.size(); i++)
    {
        for (auto u : graph[q[i]])
        {
            if (dist[u] == -1)
            {
                dist[u] = dist[q[i]] + 1;
                q.push_back(u);
            }
        }
    }
}

ll log10(ll x)
{
    if (x < 10) re 1;
    re 1 + log10(x / 10);
}

double sqr(double x)
{
    return x * x;
}

signed main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);
    ll h, w, a, b, c, n;
    cin >> h >> w >> a >> b >> c >> n;
    vll x(n), y(n);
    forn(i, n) cin >> x[i] >> y[i];
    vll dp(n, INFLL);
    vi r(n, 0);
    dp[0] = 0;
    for (int i = 0; i < n; i++)
    {
        ll minc = INFLL, id = -1;
        for (int j = 0; j < n; j++)
        {
            if (r[j] == 0 && dp[j] < minc)
            {
                minc = dp[j];
                id = j;
            }
        }
        r[id] = 1;
        for (int j = 0; j < n; j++)
        {
            ll v = min(abs(x[id] - x[j]), abs(y[id] - y[j])) * c + b;
            dp[j] = min(dp[j], dp[id] + v);
        }
    }
    cout << dp[n - 1];
}

/* Note:
Check constants at the beginning of the code.
    N is set to 4e5 but be careful in problems with large constant factor.
    Setting N in every problem is more effective.
Check corner cases.
    N = 1
No def int long long for now.
Add something here.
*/

Compilation message

soccer.cpp: In function 'void bfs(int, vi&, std::vector<std::vector<int> >&)':
soccer.cpp:114:23: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
     for (int i = 0; i < q.size(); i++)
                     ~~^~~~~~~~~~

Subtask #1
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 6 ms 384 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #2
30.0 / 30.0

# 결과 실행 시간 메모리 Grader output
1 Correct 5 ms 384 KB Output is correct
2 Correct 5 ms 384 KB Output is correct
3 Correct 5 ms 384 KB Output is correct
4 Correct 5 ms 384 KB Output is correct
5 Correct 5 ms 384 KB Output is correct
6 Correct 10 ms 384 KB Output is correct
7 Correct 12 ms 384 KB Output is correct
8 Correct 14 ms 384 KB Output is correct
9 Correct 11 ms 384 KB Output is correct
10 Correct 10 ms 384 KB Output is correct
11 Correct 11 ms 384 KB Output is correct
12 Correct 5 ms 384 KB Output is correct
13 Correct 12 ms 384 KB Output is correct
14 Correct 11 ms 384 KB Output is correct
15 Correct 10 ms 384 KB Output is correct

Subtask #3
0 / 65.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 6 ms 384 KB Output isn't correct
2 Halted 0 ms 0 KB -